使用sed在两种模式之间打印

Question

所以我发现很多deleting the text between two patterns和printing the text between two delimiters，但是我还没有发现使用bash函数在两个模式之间打印文本的任何内容。

如果我有：

"Alas poor Yorik, I knew him well" 

，我想模式之间打印一切“穷”与“井”（独家）我会得到：

" Yorik, I knew him " 

我怎么能做到这一点使用类似sed或awk的东西？

Answer 1

dtpwmbp:~ pwadas$ echo "Alas poor Yorik, I knew him well" | sed -e 's/^.*poor //g;s/ well.*$//g' 
Yorik, I knew him 
dtpwmbp:~ pwadas$ echo "Alas poor Yorik, I knew him well" | awk '{sub(/.*poor /,"");sub(/ well.*/,"");print;}' 
Yorik, I knew him 

用法与文件输入：

dtpwmbp:~ pwadas$ echo "Alas poor Yorik, I knew him well" > infile 
dtpwmbp:~ pwadas$ cat infile 
Alas poor Yorik, I knew him well 
dtpwmbp:~ pwadas$ cat infile | sed -e 's/^.*poor //g;s/ well.*$//g' 
Yorik, I knew him 
dtpwmbp:~ pwadas$ sed -e 's/^.*poor //g;s/ well.*$//g' < infile 
Yorik, I knew him 
dtpwmbp:~ pwadas$ cat infile | awk '{sub(/.*poor /,"");sub(/ well.*/,"");print;}' 
Yorik, I knew him 
dtpwmbp:~ pwadas$ awk '{sub(/.*poor /,"");sub(/ well.*/,"");print;}' < infile 
Yorik, I knew him