替换字符串中的亵渎词的正则表达式

Question

我试图用文本字符串替换一组单词。现在我有一个循环，不执行得好：

function clearProfanity(s) { 
    var profanity = ['ass', 'bottom', 'damn', 'shit']; 
    for (var i=0; i < profanity.length; i++) { 
     s = s.replace(profanity[i], "###!"); 
    } 
    return s; 
} 

我想要的东西，工作速度更快，并且东西，这将与具有相同长度的原词###!马克更换坏词。

Answer 1

看到它的工作： http://jsfiddle.net/osher/ZnJ5S/3/

这基本上是：

var PROFANITY = ['ass','bottom','damn','shit'] 
    , CENZOR = ("#####################").split("").join("########") 
    ; 
PROFANITY = new RegExp("(\\W)(" + PROFANITY.join("|") + ")(\\W)","gi"); 

function clearProfanity(s){ 
    return s.replace(PROFANITY 
        , function(_,b,m,a) { 
         return b + CENZOR.substr(0, m.length - 1) + "!" + a 
         } 
        ); 
} 


alert(clearProfanity("'ass','bottom','damn','shit'")); 

这将是更好，如果PROFANITY阵列将启动一个字符串，或更好 - 直接作为正则表达式：

//as string 
var PROFANITY = "(\\W)(ass|bottom|damn|shit)(\\W)"; 
PROFANITY = new RegExp(PROFANITY, "gi"); 

//as regexp 
var PROFANITY = /(\W)(ass|bottom|damn|shit)(\W)/gi 

Answer 2

以下是一种方法：

String.prototype.repeat = function(n){ 
    var str = ''; 
    while (n--){ 
     str+=this; 
    } 
    return str; 
} 

var re = /ass|bottom|damn|shit/gi 
    , profane = 'my ass is @ the bottom of the sea, so shit \'nd damn'; 

alert(profane.replace(re,function(a) {return '#'.repeat(a.length)})); 
//=>my ### is @ the ###### of the sea, so #### 'n #### 

是完整的：这里有一个简单的方法来做到这一点，以字边界考虑：

var re = /\W+(ass|shit|bottom|damn)\W+/gi 
     , profane = [ 'My cassette of forks is at the bottom' 
        ,'of the sea, so I will be eating my shitake' 
        ,'whith a knife, which can be quite damnable' 
        ,'ambassador. So please don\'t harrass me!' 
        ,'By the way, did you see the typo' 
        ,'in "we are sleepy [ass] bears"?'] 
        .join(' ') 
        .replace(re, 
           function(a){ 
           return a.replace(/[a-z]/gi,'#'); 
           } 
        ); 
alert(profane);