将数据发送到PHP服务器

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我想30秒后，发送经纬度长....对于将数据发送到PHP服务器

我使用，

if (theDiff > 30.0f || myDate == nil){ 
     //do your webservices stuff here 
     NSLog(@"Location get ==================="); 
     double lat = newLocation.coordinate.latitude; 
     double longt = newLocation.coordinate.longitude; 


     NSString *ids = [NSString stringWithFormat:@"%d",[[NSUserDefaults standardUserDefaults]integerForKey:CURRENT_USERID]]; 
     ASIFormDataRequest *request = [ASIFormDataRequest requestWithURL:[NSURL URLWithString:UPDATE_LATLONG]]; 

     [request setPostValue:[NSNumber numberWithDouble: lat] forKey:@"latitude"]; 
     [request setPostValue:[NSNumber numberWithDouble: longt] forKey:@"longitude"]; 
     [request setPostValue:ids forKey:@"userid"]; 
     [request startSynchronous]; 

     NSString *XMLResponseString = [request responseString]; 
     NSLog(@"XMLResponseString %@",XMLResponseString); 
     [request release]; 

      NSLog(@"lat = %.6f",lat); 
      NSLog(@"long = %.6f",longt); 
     NSUserDefaults *prefs = [NSUserDefaults standardUserDefaults]; 
     [prefs setObject:lastDate forKey:@"myDateKey"]; 
     [prefs synchronize]; 
    }

但给人错误...

2012-03-01 15:01:43.352 BiiMe[1638:207] +[NSString stringwithFormat:]: unrecognized selector sent to class 0x447fd8 
sharedlibrary apply-load-rules all 
(gdb)

我错了什么？

来源

2012-03-01 Siten

也许你使用'stringwithFormat'而不是'stringWithFormat' – Bonny 2012-03-01 09:23:08

请尝试使用更多的CodeSense功能。

这stringWithFormat:不stringwithFormat:

希望这有助于你。

来源

2012-03-01 09:25:25

雅但我在哪里写？＆错误是我粘贴从我的Xcode。 – Siten 2012-03-01 09:37:34

只需在您的项目中搜索字符串stringwithFormat并将其替换为stringWithFormat – 2012-03-01 09:40:07

将数据发送到PHP服务器

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