查询嵌入文档匹配多个属性

我有以下结构：查询嵌入文档匹配多个属性

class User 
    include Mongoid::Document 
end 

class Resource 
    include Mongoid::Document 
    embeds_many :permissions 
end 

class Permission 
    include Mongoid::Document 
    embedded_in :resource 

    field :read, type: Boolean 
    field :write, type: Boolean 

    field :user_id, type: BSON::ObjectId 
end

现在让我们假设我有以下数据：

1.9.3p194 :001 > a = User.create 
=> #<User _id: 4ff46818f83222daf9000001, _type: nil> 
1.9.3p194 :002 > b = User.create 
=> #<User _id: 4ff4681bf83222daf9000002, _type: nil> 
1.9.3p194 :003 > r = Resource.create 
=> #<Resource _id: 4ff46822f83222daf9000003, _type: nil> 
1.9.3p194 :004 > r.permissions.create(read: true, user_id: a.id) 
=> #<Permission _id: 4ff46835f83222daf9000004, _type: nil, read: true, write: nil, user_id: 4ff46818f83222daf9000001> 
1.9.3p194 :005 > r.permissions.create(read: true, write: true, user_id: b.id) 
=> #<Permission _id: 4ff4684af83222daf9000005, _type: nil, read: true, write: true, user_id: 4ff4681bf83222daf9000002>

现在我想找到用户A拥有所有资源写访问（应该是none）

1.9.3p194 :007 > Resource.where('permissions.write' => true).where('permissions.user_id' => a.id).all.entries 
=> [#<Resource _id: 4ff46822f83222daf9000003, _type: nil>]

这显然失败了，因为对于每个where子句有匹配。这将是什么正确的解决方案？有没有办法为嵌入式文档查询做and？

来源

2012-07-04 mxhaack

试试这个

Resource.where(:permissions.matches => {:write => true, :user_id => a.id}).all

来源

2012-07-04 19:23:50 abhas

这似乎是正确的mongoid2。因为我使用的是mongoid3（应该提到）解决方案是：'Resource.where（：permissions.elem_match => {：write => true，：user_id => a.id}）' – mxhaack

-1

试试这个：

Resource.Permission.where（写：真，USER_ID：a.id）

来源

2012-07-04 18:12:26 GBD

将返回：'NoMethodError：未定义的方法'权限'资源：类' – mxhaack

查询嵌入文档匹配多个属性

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