我查询从数据库中,有超过一个结果应查询结果。但是,当我试图显示查询的结果时,只显示一个结果,所以我尝试使用foreach函数,但它仍然不起作用。我被打败了,不知道我做错了什么。任何人都知道发生了什么问题?的MySQL/PHP的foreach仍然只能显示第一数据库
这里的MySQL查询代码:
<?php
//Database Information
$dbhost = "";
$dbname = "";
$dbuser = "";
$dbpass = "";
//Connect to database
mysql_connect ($dbhost, $dbuser, $dbpass)or die("Could not connect: ".mysql_error());
mysql_select_db($dbname) or die(mysql_error());
$filename = $_GET['filename'];
$new_captions = mysql_query("SELECT * from captions where image = 'http://math.stanford.edu/inc/img/PalmDrive.png' ORDER BY idnum DESC LIMIT 5");
while($rows = mysql_fetch_array($new_captions)){
$caption = $rows;
}
?>
而这里的的foreach:
<?php foreach($caption as $rows) {?>
<div id="set_caption" style="width:<?php echo $caption['width'];?>px; height:<?php echo $caption['height'];?>px; left:<?php echo $caption['posleft'];?>px; top:<?php echo $caption['postop'];?>px;"><?php echo $caption['text'];?></div>
<?php } ?>
它总是存储在最后一个值,因为要覆盖$标题的每执行一次循环的值。相反,你要遵循罗伯特的正确方法。 –