2009-04-16 53 views

回答

1

如何使用dateDiff函数?

DECLARE @Dt INT 
SET @Dt = DATEDIFF(dd,@StartDate,@EndDate) 

应该做的伎俩?

还是我错过了什么?

12

DateDiff函数应该做你需要什么

declare @var1 Datetime 
declare @var2 Datetime 

set @var1 = '2009-04-01' 
set @var2 = '2009-04-16' 

SELECT datediff(day,@var1, @var2) 
+0

@ VAR1,@ VAR2 =坏话:) – 2009-04-16 08:45:33

1
USE tempdb 

DECLARE @DATE1 datetime 

DECLARE @DATE2 datetime 

SET @DATE1 = '01/01/2000' 

SET @DATE2 = '02/01/2000' 

SELECT DATEDIFF(day, @DATE1, @DATE2) 
0

DATEDIFF是做

0

注意的方式,仅DATEDIFF本身涉及的日期部分。如果涉及时间,转换后的减法可能会产生更好的结果。

DECLARE @start DATETIME 
DECLARE @end DATETIME 
SET @start = '20090514 00:00:00' 
SET @end = '20090514 23:59:59' 
PRINT CONVERT(FLOAT, (@[email protected])) -- 0.999988 
PRINT DATEDIFF(DAY,@start,@end)  -- 0