嵌套n：m +属性JPA

我在项目中有一个奇怪的需求。加入两个n：m +属性表（我将用虚拟属性呈现行为）。嵌套n：m +属性JPA

FirstTable（idPlace，idAddress，idSchool，wage）joined 1：m;
SecondTable（idPlace，idAddress，idSchool，数量，idEnterprise）

EDIT（例如模式）：

当然，我有表地点，住址，学校，企业与他们各自的在实体类中实现的Ids，获取，集合和属性。

CODE：

广场

@Entity 
@Table(name = "Place") 
public class Place implements Serializable { 

/** 
* 
*/ 
private static final long serialVersionUID = 1L; 
@Id 
@GeneratedValue(strategy = GenerationType.AUTO) 
@Column(name = "idLine") 
private Long idLine; 

@OneToMany(fetch = FetchType.LAZY, cascade = CascadeType.ALL, mappedBy = "pk.place") 
private List<FirstTable> firstTables; 
}

地址

@Entity 
@Table(name = "Address") 
public class Address implements Serializable { 

/** 
* 
*/ 
private static final long serialVersionUID = 1L; 
@Id 
@GeneratedValue(strategy = GenerationType.AUTO) 
@Column(name = "idAddress") 
private Long idAddress; 

@OneToMany(fetch = FetchType.LAZY, cascade = CascadeType.ALL, mappedBy = "pk.address") 
private List<FirstTable> firstTables; 
}

学校

@Entity 
@Table(name = "School") 
public class School implements Serializable { 

/** 
* 
*/ 
private static final long serialVersionUID = 1L; 
@Id 
@GeneratedValue(strategy = GenerationType.AUTO) 
@Column(name = "idSchool") 
private Long idSchool; 

@OneToMany(fetch = FetchType.LAZY, cascade = CascadeType.ALL, mappedBy = "pk.school") 
private List<FirstTable> firstTables; 
}

FirstTable

@Entity 
@Table(name = "FirstTable") 
@AssociationOverrides({ @AssociationOverride(name = "pk.school", joinColumns = @JoinColumn(name = "idSchool")), 
    @AssociationOverride(name = "pk.address", joinColumns = @JoinColumn(name = "idAddress")), 
    @AssociationOverride(name = "pk.place", joinColumns = @JoinColumn(name = "idPlace")) }) 
public class FirstTable implements Serializable { 

/** 
* 
*/ 
private static final long serialVersionUID = 1L; 

@EmbeddedId 
protected FirstTablePK pk = new FirstTablePK(); 
}

FirstTablePK

@Embeddable 
public class FirstTablePK implements Serializable{ 

/** 
* 
*/ 
private static final long serialVersionUID = 1L; 
@ManyToOne 
private Address address; 
@ManyToOne 
private Place place; 
@ManyToOne 
private School school; 
}

上面提到的表和联接是完全工作。现在我想加入First Table和Second Table。

企业

@Entity 
@Table(name = "Enterprise") 
public class Enterprise implements Serializable { 

private static final long serialVersionUID = 1L; 
@Id 
@GeneratedValue(strategy = GenerationType.AUTO) 
@Column(name = "idEnterprise") 
private Long idEnterprise;

@OneToMany（取= FetchType.LAZY，级联= CascadeType.ALL，的mappedBy = “pk.enterprise”）私人列表secondTables;现在 }

为SecondTable我已经遵循同样的逻辑，其连接到企业。为了与FirstTable连接我试过这样：

@Entity 
@Table(name = "SecondTable") 
@AssociationOverrides({ 
     @AssociationOverride(name = "pk.firstTable", joinTable = @JoinTable(
       name = "FirstTable", inverseJoinColumns = { 
       @JoinColumn(name = "idSchool", referencedColumnName = "idSchool"), 
       @JoinColumn(name = "idAddress", referencedColumnName = "idAddress"), 
       @JoinColumn(name = "idPlace", referencedColumnName = "idPlace") })), 
     @AssociationOverride(name = "pk.enterprise", joinColumns = @JoinColumn(name = "idEnterprise")) }) 
public class SecondTable implements Serializable{}

自己是不是在我的注释工作，我试图做一个inverseJoin到FirstTable表。汇编显示此错误：

"org.hibernate.AnnotationException: A component cannot hold properties split into 2 different tables"

我试图提供一个MV示例。在此先感谢，我真的需要你的帮助。

来源

2016-12-05 Ricardo

几小时后，许多尝试之前，我已经设法解决问题。事实上，我最初想的解决方案要简单得多。

这就是：

@AssociationOverride(name = "pk.firstTable", joinColumns = { 
      @JoinColumn(name = "idSchool"), 
      @JoinColumn(name = "idAddress"), 
      @JoinColumn(name = "idPlace") }), 
    @AssociationOverride(name = "pk.enterprise", joinColumns = @JoinColumn(name = "idEnterprise")) })

来源

2016-12-05 17:22:42 Ricardo

嵌套n：m +属性JPA

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