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我有一个窗体中有一个文本字段。用户在文本字段中输入电子邮件地址,并且当用户提交表单时,Action
类会从Users
表中找到用户的uid
,并在JSP页面上显示uid
作为<s:actionmessage/>
的消息。我得到一个IndexOutOfBoundsException
。java.lang.IndexOutOfBoundsException:索引:0,大小:0
我的JSP的形式是:
<s:form action="okadddqs" method="post" cssClass="text">
<s:textfield label="Your Email address " name="email"/>
<s:submit value="Find Uid"/>
</s:form>
为Action
类的代码是:
package com.rambo.action;
import beans.Users;
import com.opensymphony.xwork2.ActionSupport;
import java.util.ArrayList;
import java.util.List;
import java.util.StringTokenizer;
import javax.faces.bean.ManagedBean;
import javax.faces.bean.SessionScoped;
import org.hibernate.Session;
/**
*
* @author ROMO
*/
@ManagedBean
@SessionScoped
public class NewQuestion extends ActionSupport {
private String email;
private List<Users> ul = new ArrayList<Users>();
public List<Users> getUl() {
return ul;
}
public void setUl(List<Users> ul) {
this.ul = ul;
}
public String getEmail() {
return email;
}
public void setEmail(String email) {
this.email = email;
}
/* i have used many where the getUid() and getEmail() even in the error and messages to find what the value it is getting on error. */
@Override
public String execute() throws Exception {
Session session = null;
int d;
try {
session = HibernateUtil.getSessionFactory().getCurrentSession();
session.beginTransaction();
try {
ul = (List<Users>) session.createQuery("from Users c where c.email = '" + getEmail() + "'");
if (!ul.isEmpty()) {
d = ul.get(0).getUid();
} else {
this.addActionError("Oops. Sorry. You are Not Allowed now. Please Try Again Later." + getEmail() + ","+ ul.get(0).getUid());
session.close();
return ERROR;
}
} catch (Exception e) {
this.addActionError("Oops. There was an error." + getEmail() + ","+ ul.get(0).getUid());
session.close();
return ERROR;
}
session.getTransaction().commit();
} catch (Exception e) {
this.addActionError("Oops. An Error Encountered...! Email address " + getEmail() + ","+ ul.get(0).getUid()+" not registered. Try with your new email address.");
session.close();
return ERROR;
}
this.addActionMessage("Your Uid is : " + ul.get(0).getUid());
return SUCCESS;
}
@Override
public void validate() {
if ("".equals(getEmail()) || getEmail() == null) {
this.addActionError("Email is Compulsory to input..!" + getCname());
} else if (getEmail().indexOf("@") < 0 || getEmail().indexOf(",") > 0 || getEmail().indexOf(".") < 0 || lastEmailFieldTwoCharsOrMore(getEmail()) == false) {
this.addActionError("Please Input a valid email address." + getCname());
}
}
}
当我删除所有的try catch块我得到的例外是:
java.lang.ClassCastException: org.hibernate.impl.QueryImpl cannot be cast to java.util.List
我已经用POJO正确地完成了表和bean的映射。有人可以指出错误吗?我在Struts中使用Hibernate。
请发布有关该异常的完整堆栈跟踪。 – Lion 2012-07-14 04:39:33
抱歉,但事实上,我没有在glassfish服务器日志上收到任何堆栈跟踪错误。然而唯一的例外是在浏览器上看到的。 – codeofnode 2012-07-14 04:43:00
这是因为你用'try ... catch'捕获异常。暂时注释这个'try ... catch',你会得到堆栈跟踪。这只是因为只有在他/她查看堆栈跟踪之后,某人才能更好地猜测异常的确切原因。 – Lion 2012-07-14 04:47:29