用逗号或不替换字符串的preg_replace

我有这个值格式的字符串：用逗号或不替换字符串的preg_replace

$str = "Apple, Orange, Computer-Hardware, preg_replace, 50k";

或

$str = "Computer";

我怎么能与preg_replace函数将其转换为：

$str = "<a href='p.php?s=Apple'>Apple</a>, <a href='p.php?s=Orange'>Orange</a>, 
<a href='p.php?s=Computer-Hardware'>Computer-Hardware</a>, <a href='p.php?s=preg_replace'>preg_replace</a>, <a href='p.php?s=50k'>50k</a>"; 

$str = "<a href='p.php?s=Computer'>Computer</a>";

来源

2012-02-19 Ali

$str = preg_replace('/([\w-]+)/', '<a href=\'p.php?s=$1\'>$1</a>', $str);

来源

2012-02-19 00:03:39

在某些词之间的字符串可以是这两个字符 - ，_或数字：前：浸渍料-replcae，56K，50000 – Ali 2012-02-19 00:58:44

@AliA：我已经更新了我的答案。 – 2012-02-19 01:09:00

@TimCoorper：结果中逗号也用“Apple,” – Ali 2012-02-19 02:45:35

试试看：

$str = "Apple, Orange, Computer-Hardware, preg_replace, 50k"; 
$str = preg_replace('/([^,\s]+)/', "<a href='p.php?s=$1'>$1</a>", $str); 
echo $str,"\n";

输出：

<a href='p.php?s=Apple'>Apple</a>, <a href='p.php?s=Orange'>Orange</a>, <a href='p.php?s=Computer-Hardware'>Computer-Hardware</a>, <a href='p.php?s=preg_replace'>preg_replace</a>, <a href='p.php?s=50k'>50k</a>

来源

2012-02-19 10:35:34 Toto

用逗号或不替换字符串的preg_replace

回答

相关问题