如何分割文本文件

Question

文本文件中的行：

$3.00,0.00,0.00,1.00,L55894M8,$3.00,0.00,0.00,2.00,L55894M9 

如何分割线，并得到像L55894M8和L55894M9序列号？

Answer 1

在您的样品，你意味着想要得到词语的指数（4,9，14 ....）

而且五个字作为一个政党。

所以，你可以试试这个方法.....

static void Main(string[] args) 
    { 
     string strSample = "$3.00,0.00,0.00,1.00,L55894M8,$3.00,0.00,0.00,2.00,L55894M9"; 
     var result = from p in strSample.Split(',').Select((v, i) => new { Index = i, Value = v }) 
        where p.Index % 5 == 4 
        select p.Value; 

     foreach (var r in result) 
     { 
      Console.WriteLine(r); 
     } 

     Console.ReadKey(); 
    } 

Answer 2

如果该文件是在一个字符串可以使用该字符串的.split(',')方法然后检查所得到的数组的每个元素。或者，如果数据的模式在整个可见抓住每5个元素。

Answer 3

var str = "$3.00,0.00,0.00,1.00,L55894M8,$3.00,0.00,0.00,2.00,L55894M9"; 
var fieldArray = str.Split(new[] { ',' }); 
var serial1 = fieldArray[4]; // "L55894M8" 
var serial2 = fieldArray[9]; // "L55894M9" 

Answer 4

要获得的第4个逗号和第9逗号后出现的数据，你会想做的事：

var pieces = line.Split(','); 
var serial1 = line[3]; 
var serial2 = line[8]; 

编辑：在进一步思考，似乎你的文件有以$开头的记录并以下一个记录结束。如果你想要这些记录以及序列号（它似乎是最后一个字段），你可以这样做：

var records = line.TrimStart('$').Split('$'); 
var recordObjects = records.Select(r => new { Line = r, Serial = r.TrimEnd(',').Split(',').Last() }); 

Answer 5

尝试正则表达式。

string str = "$3.00,0.00,0.00,1.00,L55894M8,$3.00,0.00,0.00,2.00,L55894M9"; 
string pat = @"L[\w]+"; 

MatchCollection ar= Regex.Matches(str, pat); 

foreach (var t in ar) 
    Console.WriteLine(t);