合并重复达

Question

假设我有这个JArray：

{ 
    "ArrayofItem":{ 
     "Item":[ 
     { 
      "Amount": "1.52" 
      "Date": "05/01/2015" 
     }, 
     { 
      "Amount": "2.52" 
      "Date": "05/01/2015" 
     }, 
     { 
      "Amount": "5.62" 
      "Date": "05/02/2015" 
     }, 
     { 
      "Amount": "1.06" 
      "Date": "05/02/2015" 
     }, 
     { 
      "Amount": "6.30" 
      "Date": "05/03/2015" 
     }, 
     { 
      "Amount": "1.00" 
      "Date": "05/04/2015" 
     }, 
     { 
      "Amount": "1.55" 
      "Date": "05/04/2015" 
     }, 
     { 
      "Amount": "1.63" 
      "Date": "05/05/2015" 
     }, 
     { 
      "Amount": "1.78" 
      "Date": "05/06/2015" 
     } 
    } 
} 

我怎样才能巩固项目，以便在同一日期的所有项目都结合在一起，形成一个新的JArray这样的：

{ 
    "ArrayofItem":{ 
     "Item":[ 
     { 
      "Amount": "4.04" 
      "Date": "05/01/2015" 
     }, 
     { 
      "Amount": "6.68" 
      "Date": "05/02/2015" 
     }, 
     { 
      "Amount": "6.30" 
      "Date": "05/03/2015" 
     }, 
     { 
      "Amount": "2.55" 
      "Date": "05/04/2015" 
     }, 
     { 
      "Amount": "1.63" 
      "Date": "05/05/2015" 
     }, 
     { 
      "Amount": "1.78" 
      "Date": "05/06/2015" 
     } 
    } 
} 

本质上，我需要按原始项目的日期列表进行汇总。您可以假定这些项目已按日期排序。

Answer 1

您可以使用下面的代码为你的模型：

public class Rootobject 
{ 
    public Arrayofitem ArrayofItem { get; set; } 
} 

public class Arrayofitem 
{ 
    public Item[] Item { get; set; } 
} 

public class Item 
{ 
    public string Amount { get; set; } 
    public string Date { get; set; } 
} 

，然后这个代码将做的工作：

string jsonText = "your json text goes here...";  
var o = JsonConvert.DeserializeObject<Rootobject>(jsonText); 
var itemArray = o.ArrayofItem.Item 
          .GroupBy(item => item.Date, (date, item) => 
            new Item 
            { 
             Date = date, 
             Amount = item.Sum(i => float.Parse(i.Amount)).ToString() 
            }).ToArray(); 

string serializedGroup = JsonConvert.SerializeObject(new Rootobject { ArrayofItem = new Arrayofitem { Item = itemArray } }); 

Answer 2

如果你想与LINQ to JSON纯粹做到这一点，你可以使用GroupBy和Sum创建必要的对象：

 var obj = JObject.Parse(json); 
     var query = obj.SelectTokens("ArrayofItem.Item") 
      .SelectMany(t => t) 
      .OfType<JObject>() 
      .GroupBy(o => o["Date"], o => o["Amount"]) 
      .Select(g => new JObject(new JProperty("Amount", g.Sum(a => (decimal)a)), new JProperty("Date", g.Key))); 
     var newObj = new JObject(new JProperty("ArrayofItem", new JObject(new JProperty("Item", new JArray(query)))));