合并使用XSLT两个XML文件中读取第三xml文件

Question

后，我有一个XML文件，如下 propNode.xml

<NODES> 
    <NODE> 
<NODELINE CLASS="Item" TYPE="Item" > 
    <ATTR_NODES> 
    <ATTR_NODE NAME="myName" /> 
    <ATTR_NODE NAME="myDesc /> 
    </ATTR_NODES> 
</NODELINE> 
<NODELINE CLASS="Item1" TYPE="Item1" > 
    <ATTR_NODES> 
    <ATTR_NODE NAME="myName1" /> 
    <ATTR_NODE NAME="myDesc1" /> 
    </ATTR_NODES> 
</NODELINE> 
<NODELINE CLASS="Item2" TYPE="Item2" > 
    <ATTR_NODES> 
    <ATTR_NODE NAME="myName2" /> 
    <ATTR_NODE NAME="myDesc2" /> 
    </ATTR_NODES> 
</NODELINE> 
</NODE> 
</NODES> 

我想读这个XML和使用它，我需要合并以下两个XML文件 source.xml

<NODES> 
    <NODE> 
<NODELINE CLASS="Item" TYPE="Item" > 
    <ATTR_NODES> 
    <ATTR_NODE NAME="myName" VALUE="myNameValue" /> 
    <ATTR_NODE NAME="myDesc" VALUE="test-myDescValue" /> 
<ATTR_NODE NAME="myId" VALUE="test-myIdValue" /> 
    </ATTR_NODES> 
</NODELINE> 
<NODELINE CLASS="Item1" TYPE="Item1" > 
    <ATTR_NODES> 
    <ATTR_NODE NAME="myName1" VALUE="myNameValue1" /> 
    <ATTR_NODE NAME="myDesc1" VALUE="myDescValue1"/> 
<ATTR_NODE NAME="myId1" VALUE="myIdValue1" /> 
    </ATTR_NODES> 
</NODELINE> 
<NODELINE CLASS="Item2" TYPE="Item2" > 
    <ATTR_NODES> 
    <ATTR_NODE NAME="myName2" VALUE="test-myNameValue2" /> 
    <ATTR_NODE NAME="myDesc2" VALUE="myDescValue2"/> 
<ATTR_NODE NAME="myId2" VALUE="test-myIdValue2" /> 
    </ATTR_NODES> 
</NODELINE> 
    </NODE> 
</NODES> 

而且target.xml

<NODES> 
    <NODE> 
<NODELINE CLASS="Item" TYPE="Item" > 
    <ATTR_NODES> 
    <ATTR_NODE NAME="myName" VALUE="myNameValue" /> 
    <ATTR_NODE NAME="myDesc" VALUE="myDescValue" /> 
<ATTR_NODE NAME="myId" VALUE="myIdValue" /> 
    </ATTR_NODES> 
</NODELINE> 
<NODELINE CLASS="Item1" TYPE="Item1" > 
    <ATTR_NODES> 
    <ATTR_NODE NAME="myName1" VALUE="myNameValue1" /> 
    <ATTR_NODE NAME="myDesc1" VALUE="myDescValue1"/> 
<ATTR_NODE NAME="myId1" VALUE="myIdValue1" /> 
    </ATTR_NODES> 
</NODELINE> 
<NODELINE CLASS="Item2" TYPE="Item2" > 
    <ATTR_NODES> 
    <ATTR_NODE NAME="myName2" VALUE="myNameValue2" /> 
    <ATTR_NODE NAME="myDesc2" VALUE="myDescValue2"/> 
<ATTR_NODE NAME="myId2" VALUE="myIdValue2" /> 
    </ATTR_NODES> 
</NODELINE> 
    </NODE> 
</NODES> 

条件正在读取propNode.xml，如果@NAME的值在source.xml和target.xml匹配，则@VALUE在source.xml和target.xml的值需要进行比较，并输出XML应如下创建：

desiredOutput.xml

<NODES> 
    <NODE> 
<NODELINE CLASS="Item" TYPE="Item" > 
    <ATTR_NODES> 
    <ATTR_NODE NAME="myName" SRCVALUE="myNameValue" TGTVALUE="myNameValue" ISDIFF="false" /> 
    <ATTR_NODE NAME="myDesc" SRCVALUE="test-myDescValue" TGTVALUE="myDescValue" ISDIFF="true" /> 
    </ATTR_NODES> 
</NODELINE> 
<NODELINE CLASS="Item1" TYPE="Item1" > 
    <ATTR_NODES> 
    <ATTR_NODE NAME="myName1" SRCVALUE="myNameValue1" TGTVALUE="myNameValue1" ISDIFF="false" /> 
    <ATTR_NODE NAME="myDesc1" SRCVALUE="myDescValue1" TGTVALUE="myDescValue1" ISDIFF="false" /> 
    </ATTR_NODES> 
</NODELINE> 
<NODELINE CLASS="Item2" TYPE="Item2" > 
    <ATTR_NODES> 
    <ATTR_NODE NAME="myName2" SRCVALUE="test-myNameValue2" TGTVALUE="myNameValue2" ISDIFF="true" /> /> 
    <ATTR_NODE NAME="myDesc2" SRCVALUE="myDescValue2" TGTVALUE="myDescValue2" ISDIFF="false" /> 
    </ATTR_NODES> 
</NODELINE> 
    </NODE> 
</NODES> 

的desiredOutput.xml应从源同时包含@VALUE的值与目标如果值在propNode.xml中选择了@NAME。如果@VALUE的值不同，@ISDIFF应该有一个值“true”或者“false”。

使用xslt可以完成整个操作吗？就像使用propNode.xml生成xsl然后将其应用于source.xml和target.xml以生成所需的输出一样？这个xsl看起来怎么样？

Answer 1

假设只有节点（ATTR_NODE）目前在propNode.xml需要进行测试，下面的XSLT应该做的工作：

<?xml version="1.0" encoding="UTF-8"?> 
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
    xmlns:my="some.uri" version="1.0"> 

    <xsl:template match="@*|node()"> 
     <xsl:copy> 
      <xsl:apply-templates select="@* | node()"/> 
     </xsl:copy> 
    </xsl:template> 

    <xsl:template match="ATTR_NODE"> 
     <xsl:variable name="NodeLine" select="../../@CLASS" /> 
     <xsl:variable name="AttrName" select="@NAME" /> 
     <xsl:variable name="SrcValue" select="document('source.xml')//NODELINE[@CLASS=$NodeLine]//ATTR_NODE[@NAME=$AttrName]/@VALUE" /> 
     <xsl:variable name="TgtValue" select="document('target.xml')//NODELINE[@CLASS=$NodeLine]//ATTR_NODE[@NAME=$AttrName]/@VALUE" /> 
     <xsl:element name="ATTR_NODE"> 
      <xsl:attribute name="NAME"> 
       <xsl:value-of select="$AttrName"/> 
      </xsl:attribute> 
      <xsl:attribute name="SRCVALUE"> 
       <xsl:value-of select="$SrcValue" /> 
      </xsl:attribute> 
      <xsl:attribute name="TGTVALUE"> 
       <xsl:value-of select="$TgtValue" /> 
      </xsl:attribute> 
      <xsl:attribute name="ISDIFF"> 
       <xsl:value-of select="$SrcValue!=$TgtValue" /> 
      </xsl:attribute> 
     </xsl:element> 
    </xsl:template> 
</xsl:stylesheet> 

身份模板用于遍历和复制propNode，具有特殊处理每个ATTR_NODE检查源和目标中的VALUE，然后评估其是否相等。我假设NODE_LINE/@CLASS足以确定NODE_LINE的身份 - 如果不是，那么您需要添加其他检查功能，例如， @TYPE。

xslt针对propnode.xml运行，并且source.xml和target.xml必须存在于相同的文件夹中。

输出

<?xml version="1.0" encoding="utf-8"?> 
<NODES> 
    <NODE> 
     <NODELINE CLASS="Item" TYPE="Item"> 
      <ATTR_NODES> 
       <ATTR_NODE NAME="myName" SRCVALUE="myNameValue" TGTVALUE="myNameValue" ISDIFF="false" /> 
       <ATTR_NODE NAME="myDesc" SRCVALUE="test-myDescValue" TGTVALUE="myDescValue" ISDIFF="true" />" 
      </ATTR_NODES> 
     </NODELINE> 
     <NODELINE CLASS="Item1" TYPE="Item1"> 
      <ATTR_NODES> 
       <ATTR_NODE NAME="myName1" SRCVALUE="myNameValue1" TGTVALUE="myNameValue1" ISDIFF="false" /> 
       <ATTR_NODE NAME="myDesc1" SRCVALUE="myDescValue1" TGTVALUE="myDescValue1" ISDIFF="false" /> 
      </ATTR_NODES> 
     </NODELINE> 
     <NODELINE CLASS="Item2" TYPE="Item2"> 
      <ATTR_NODES> 
       <ATTR_NODE NAME="myName2" SRCVALUE="test-myNameValue2" TGTVALUE="myNameValue2" ISDIFF="true" /> 
       <ATTR_NODE NAME="myDesc2" SRCVALUE="myDescValue2" TGTVALUE="myDescValue2" ISDIFF="false" /> 
      </ATTR_NODES> 
     </NODELINE> 
    </NODE> 
</NODES>