我在我的服务器上制作了一个应用程序,用户通过一些HTML结合javascript来上传图像。在JavaScript中运行PHP
用户通过
<form action="uploadimage.php" method="post"
enctype="multipart/form-data">
<label for="file">Filnavn:</label>
<input type="file" name="file" id="file" value="100000" />
然后JavaScript的后面的点在计算机上找到的图像,是验证用户图像
if(picture_headline.value == "" || picture_uploaded.value == "" || !ischecked)
{
// Don't execute, stay on same site
}
else
{
// execute php and upload image
}
PHP的是上载的图像PHP脚本
上<?php
// The file is being uploaded into the folder "upload"
$target = "/navnesutten.eu/facebook/uploads/";
// add the original filename of our target path
$target = $target . basename($_FILES['uploaded']['name']) ;
$ok=1;
// Moves the uploaded file into correct folder
if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target))
{
echo "The file ". basename($_FILES['uploadedfile']['name']). " has been uploaded";
}
else {
echo "Sorry, there was a problem uploading your file.";
}
?>
我必须说我在这里有点困惑,因为我只使用html,ph p和javascript几天。
我完全关闭或什么?
我在网上发现了一些“简单”的例子,我通过cuteFTP把它放在我的服务器上,但是每次我点击上传,网站都会把我发送到.php文件,并说网站不存在。
Java!= Javascript。 –
你有一个PHP服务器设置和运行? – Matt
你需要使用[AJAX](http://en.wikipedia.org/wiki/Ajax_(programming))来获得你想要的。 –