我想编辑悉尼主题(wordpress)的滑块按钮,为每个按钮分别设置链接,并找到以下JQuery代码。此代码运行良好,但打开当前页面中的链接。现在,我想编辑此代码以打开新选项卡中的链接。我怎么能这样做?JQuery代码打开新标签中的链接
jQuery(function($) {
//Define the new buttons. Delete the lines you don't need
var button1 = '<a href="http://www.google.com" class="roll-button button-slider">Read More</a>'; //Slide 1
var button2 = '<a href="http://www.yahoo.com" class="roll-button button-slider">Read More</a>'; //Slide 2
var button3 = '<a href="http://example.org" class="roll-button button-slider">Button 3</a>'; //Slide 3
var button4 = '<a href="http://example.org" class="roll-button button-slider">Button 4</a>'; //Slide 4
var button5 = '<a href="http://example.org" class="roll-button button-slider">Button 5</a>'; //Slide 5
//Hide the default button
$('.slide-inner a').hide();
//Add the new buttons. Delete the lines you don't need
$('.slide-item:nth-of-type(1) .slide-inner').append(button1); //Slide 1
$('.slide-item:nth-of-type(2) .slide-inner').append(button2); //Slide 2
$('.slide-item:nth-of-type(3) .slide-inner').append(button3); //Slide 3
$('.slide-item:nth-of-type(4) .slide-inner').append(button4); //Slide 4
$('.slide-item:nth-of-type(5) .slide-inner').append(button5); //Slide 5
});
的可能的复制[如何打开在HTML新标签的链接?](http://stackoverflow.com/questions/17711146/how-to-open-link-in-new-tab-on- html) – Sojtin
使用属性target = _blank在标签 –
http://stackoverflow.com/questions/17711146/how-to-open-link-in-new-tab-on-html – lordkain