Solr布尔查询与索引时间提升相结合

Question

我有一个网站使用Solr 1.4.1进行相关性/推荐。我在一些地方使用布尔型查询。我正在使用类似+(+type:aoh_company +aoh_dictionary_tids:623)的查询 - 并提供了预期的结果，但结果的顺序似乎是任意的。

我想通过设置索引时间提升来控制文档的排名，但他们似乎被忽略了这些查询。

一个例子

• 查询URL是http://localhost:4930/solr/prod/select?rows=5&start=0&q.alt=(type%3Aaoh_company)+(aoh_dictionary_tids%3A623)&q=
• 结果列于这个顺序返回（在括号中的索引时间提升值）：
  1. 17132（1.22）
  2. 17179 （1.02）
  3. 17131（1.10）
  4. 17133（1.10）
  5. 17184（1.10）
• 很明显，结果＃2不应该在＃3-5的基础上单独提高。
• 鉴于这是一个布尔查询，排名不应该有太大的差异。

调试输出

我试图通过附加debugQuery=true到查询调试上面的查询，所以它成为http://localhost:4930/solr/prod/select?rows=5&start=0&q.alt=(type%3Aaoh_company)+(aoh_dictionary_tids%3A623)&q=&debugQuery=true

这是非常详细的，但在这里它是：

<lst name="debug"> 
    <null name="rawquerystring"/> 
    <null name="querystring"/> 
    <str name="parsedquery">+(+type:aoh_company +aoh_dictionary_tids:623)</str> 
    <str name="parsedquery_toString">+(+type:aoh_company +aoh_dictionary_tids:623)</str> 
    <lst name="explain"> 
    <str name="50hves/node/17132"> 
    1.7819747 = (MATCH) sum of: 
     0.9014403 = (MATCH) weight(type:aoh_company in 1805), product of: 
     0.37135038 = queryWeight(type:aoh_company), product of: 
      2.4274657 = idf(docFreq=457, maxDocs=1909) 
      0.15297863 = queryNorm 
     2.4274657 = (MATCH) fieldWeight(type:aoh_company in 1805), product of: 
      1.0 = tf(termFreq(type:aoh_company)=1) 
      2.4274657 = idf(docFreq=457, maxDocs=1909) 
      1.0 = fieldNorm(field=type, doc=1805) 
     0.88053435 = (MATCH) weight(aoh_dictionary_tids:623 in 1805), product of: 
     0.9284928 = queryWeight(aoh_dictionary_tids:623), product of: 
      6.069428 = idf(docFreq=11, maxDocs=1909) 
      0.15297863 = queryNorm 
     0.9483481 = (MATCH) fieldWeight(aoh_dictionary_tids:623 in 1805), product of: 
      1.0 = tf(termFreq(aoh_dictionary_tids:623)=1) 
      6.069428 = idf(docFreq=11, maxDocs=1909) 
      0.15625 = fieldNorm(field=aoh_dictionary_tids, doc=1805) 
    </str> 
    <str name="50hves/node/17179"> 
    1.7819747 = (MATCH) sum of: 
     0.9014403 = (MATCH) weight(type:aoh_company in 1896), product of: 
     0.37135038 = queryWeight(type:aoh_company), product of: 
      2.4274657 = idf(docFreq=457, maxDocs=1909) 
      0.15297863 = queryNorm 
     2.4274657 = (MATCH) fieldWeight(type:aoh_company in 1896), product of: 
      1.0 = tf(termFreq(type:aoh_company)=1) 
      2.4274657 = idf(docFreq=457, maxDocs=1909) 
      1.0 = fieldNorm(field=type, doc=1896) 
     0.88053435 = (MATCH) weight(aoh_dictionary_tids:623 in 1896), product of: 
     0.9284928 = queryWeight(aoh_dictionary_tids:623), product of: 
      6.069428 = idf(docFreq=11, maxDocs=1909) 
      0.15297863 = queryNorm 
     0.9483481 = (MATCH) fieldWeight(aoh_dictionary_tids:623 in 1896), product of: 
      1.0 = tf(termFreq(aoh_dictionary_tids:623)=1) 
      6.069428 = idf(docFreq=11, maxDocs=1909) 
      0.15625 = fieldNorm(field=aoh_dictionary_tids, doc=1896) 
    </str> 
    <str name="50hves/node/17131"> 
    1.7819747 = (MATCH) sum of: 
     0.9014403 = (MATCH) weight(type:aoh_company in 1905), product of: 
     0.37135038 = queryWeight(type:aoh_company), product of: 
      2.4274657 = idf(docFreq=457, maxDocs=1909) 
      0.15297863 = queryNorm 
     2.4274657 = (MATCH) fieldWeight(type:aoh_company in 1905), product of: 
      1.0 = tf(termFreq(type:aoh_company)=1) 
      2.4274657 = idf(docFreq=457, maxDocs=1909) 
      1.0 = fieldNorm(field=type, doc=1905) 
     0.88053435 = (MATCH) weight(aoh_dictionary_tids:623 in 1905), product of: 
     0.9284928 = queryWeight(aoh_dictionary_tids:623), product of: 
      6.069428 = idf(docFreq=11, maxDocs=1909) 
      0.15297863 = queryNorm 
     0.9483481 = (MATCH) fieldWeight(aoh_dictionary_tids:623 in 1905), product of: 
      1.0 = tf(termFreq(aoh_dictionary_tids:623)=1) 
      6.069428 = idf(docFreq=11, maxDocs=1909) 
      0.15625 = fieldNorm(field=aoh_dictionary_tids, doc=1905) 
    </str> 
    <str name="50hves/node/17133"> 
    1.7819747 = (MATCH) sum of: 
     0.9014403 = (MATCH) weight(type:aoh_company in 1906), product of: 
     0.37135038 = queryWeight(type:aoh_company), product of: 
      2.4274657 = idf(docFreq=457, maxDocs=1909) 
      0.15297863 = queryNorm 
     2.4274657 = (MATCH) fieldWeight(type:aoh_company in 1906), product of: 
      1.0 = tf(termFreq(type:aoh_company)=1) 
      2.4274657 = idf(docFreq=457, maxDocs=1909) 
      1.0 = fieldNorm(field=type, doc=1906) 
     0.88053435 = (MATCH) weight(aoh_dictionary_tids:623 in 1906), product of: 
     0.9284928 = queryWeight(aoh_dictionary_tids:623), product of: 
      6.069428 = idf(docFreq=11, maxDocs=1909) 
      0.15297863 = queryNorm 
     0.9483481 = (MATCH) fieldWeight(aoh_dictionary_tids:623 in 1906), product of: 
      1.0 = tf(termFreq(aoh_dictionary_tids:623)=1) 
      6.069428 = idf(docFreq=11, maxDocs=1909) 
      0.15625 = fieldNorm(field=aoh_dictionary_tids, doc=1906) 
    </str> 
    <str name="50hves/node/17184"> 
    1.6058679 = (MATCH) sum of: 
     0.9014403 = (MATCH) weight(type:aoh_company in 1892), product of: 
     0.37135038 = queryWeight(type:aoh_company), product of: 
      2.4274657 = idf(docFreq=457, maxDocs=1909) 
      0.15297863 = queryNorm 
     2.4274657 = (MATCH) fieldWeight(type:aoh_company in 1892), product of: 
      1.0 = tf(termFreq(type:aoh_company)=1) 
      2.4274657 = idf(docFreq=457, maxDocs=1909) 
      1.0 = fieldNorm(field=type, doc=1892) 
     0.7044275 = (MATCH) weight(aoh_dictionary_tids:623 in 1892), product of: 
     0.9284928 = queryWeight(aoh_dictionary_tids:623), product of: 
      6.069428 = idf(docFreq=11, maxDocs=1909) 
      0.15297863 = queryNorm 
     0.7586785 = (MATCH) fieldWeight(aoh_dictionary_tids:623 in 1892), product of: 
      1.0 = tf(termFreq(aoh_dictionary_tids:623)=1) 
      6.069428 = idf(docFreq=11, maxDocs=1909) 
      0.125 = fieldNorm(field=aoh_dictionary_tids, doc=1892) 
    </str> 
    </lst> 
    <str name="QParser">DisMaxQParser</str> 
    <str name="altquerystring">org.apache.lucene.search.BooleanQuery:+type:aoh_company +aoh_dictionary_tids:623</str> 
    <null name="boostfuncs"/> 
    <lst name="timing"> 
    <double name="time">7.0</double> 
    <lst name="prepare"> 
     <double name="time">1.0</double> 
     <lst name="org.apache.solr.handler.component.QueryComponent"> 
     <double name="time">0.0</double> 
     </lst> 
     <lst name="org.apache.solr.handler.component.FacetComponent"> 
     <double name="time">0.0</double> 
    </lst> 
    <lst name="org.apache.solr.handler.component.MoreLikeThisComponent"> 
    <double name="time">0.0</double> 
    </lst> 
    <lst name="org.apache.solr.handler.component.HighlightComponent"> 
    <double name="time">0.0</double> 
    </lst> 
    <lst name="org.apache.solr.handler.component.StatsComponent"> 
    <double name="time">0.0</double> 
    </lst> 
    <lst name="org.apache.solr.handler.component.SpellCheckComponent"> 
    <double name="time">0.0</double> 
    </lst> 
    <lst name="org.apache.solr.handler.component.DebugComponent"> 
    <double name="time">0.0</double> 
    </lst> 
    </lst> 
    <lst name="process"> 
    <double name="time">6.0</double> 
    <lst name="org.apache.solr.handler.component.QueryComponent"> 
     <double name="time">0.0</double> 
    </lst> 
    <lst name="org.apache.solr.handler.component.FacetComponent"> 
     <double name="time">0.0</double> 
    </lst> 
    <lst name="org.apache.solr.handler.component.MoreLikeThisComponent"> 
     <double name="time">0.0</double> 
    </lst> 
    <lst name="org.apache.solr.handler.component.HighlightComponent"> 
     <double name="time">0.0</double> 
    </lst> 
    <lst name="org.apache.solr.handler.component.StatsComponent"> 
     <double name="time">0.0</double> 
    </lst> 
    <lst name="org.apache.solr.handler.component.SpellCheckComponent"> 
     <double name="time">0.0</double> 
    </lst> 
    <lst name="org.apache.solr.handler.component.DebugComponent"> 
     <double name="time">6.0</double> 
    </lst> 
    </lst> 
</lst> 

由于我读到它，前四项结果得分为1.7819747，第五项得分为1.6058679，我看不到在那里的任何提升值，所以它是eems他们不是排名方程中的一个因素。

所以我做错了什么。有什么我需要做的，以使Solr考虑到提升？
有没有办法检查存储在Solr中的boost值？它看起来正确，我发送给它的文件，但我找不到一种方法来查看存储的值？

此外，这里是从我的schema.xml相关部分：

<types> 
    <fieldType name="string" class="solr.StrField" sortMissingLast="true" omitNorms="true"/> 
    <fieldType name="integer" class="solr.IntField" omitNorms="true"/> 
</types> 
<fields> 
    <field name="type" type="string" indexed="true" stored="true"/> 
    <field name="aoh_dictionary_tids" type="integer" indexed="true" stored="true" multiValued="true" omitNorms="false"/> 
</fields> 

在下面他的回答，FYR提到的规范需要在球场上启用该提升值适用。所以我想稍微修改一下我的问题：

• 在其中一个查询字段上启用规范以便应用提升足够了吗？
• 我的omitNorms="false"在字段上是否会覆盖fieldType上的omitNorms="true"？

任何帮助将不胜感激。

Answer 1

你不会在解释中看到提升。索引时的提升适用于某个文档中某个字段的规范。像一个乘法器。

如果您启用了规范，则您的bosst值将在索引时使用。如果使用DefaultSimilarity并且启用了规范，则规范始终是相似性函数的一部分。

编辑的后续问题：

1. 这足以对应用升压启用规范。因为规范提供索引中的字段与索引中的数据权重结构。索引时间提升乘以规范值并保存到规范字段。

2. 字段声明中的omitNorms将重写类型定义 - 您在解释结构中也会看到这一点。 aoh_dictionary具有不等于1的值。如果禁用了标准1，则默认应用。