我一直在研究一段代码,它可以提取一个公会的名称,并用它来描述公会在线游戏中杀死的boss /怪物的信息。这场比赛中有许多怪物,每个人都有三个难度设置。我已经设法让代码做我想做的事情,但是它有大量的复制和粘贴,并且只能完成大约五分之一的输入。我真的不能考虑如何让这个代码少一个巨大的膨胀。这是3个难度设置中只有一个怪兽的代码,因为你可以看到它只有一个。大概还有另外60个!任何人都可以帮助我理解更好的方法来做到这一点。谢谢!使代码更有效率,更少的复制和粘贴
$sql = 'SELECT * FROM `phpbb_profile_fields_data`';
$result = $db->sql_query($sql);
while ($row = $db->sql_fetchrow($result))
{
/////////////////////////////////// START - 8 MAN BONETHRASHER
$normal = '';
$hard = '';
$nightmare = '';
/////// START - CHECK NORMAL
if ($row['pf_kp_em_no_bonethr'] == '1')
{
$normal = ' <img src="/styles/subsilver2/theme/images/soap/no.png" />';
}
else if ($row['pf_kp_em_no_bonethr'] == '2')
{
$normal = '';
}
else if (is_null($row['pf_kp_em_no_bonethr']))
{
echo "Boss was set as NULL This should not happen!";
}
else
{
echo "Sosia messed up go hit him in the face.";
}
/////// END - CHECK NORMAL
/////// START - CHECK HARD
if ($row['pf_kp_em_ha_bonethr'] == '1')
{
$hard = ' <img src="/styles/subsilver2/theme/images/soap/ha.png" />';
}
else if ($row['pf_kp_em_ha_bonethr'] == '2')
{
$hard = '';
}
else if (is_null($row['pf_kp_em_ha_bonethr']))
{
echo "Boss was set as NULL This should not happen!";
}
else
{
echo "Sosia messed up go hit him in the face.";
}
/////// END - CHECK HARD
/////// START - CHECK NIGHTMARE
if ($row['pf_kp_em_kn_bonethr'] == '1')
{
$nightmare =' <img src="/styles/subsilver2/theme/images/soap/kn.png" />';
}
else if ($row['pf_kp_em_kn_bonethr'] == '2')
{
$nightmare = '';
}
else if (is_null($row['pf_kp_em_kn_bonethr']))
{
echo "Boss was set as NULL This should not happen!";
}
else
{
echo "Sosia messed up go hit him in the face.";
}
/////// END - CHECK NIGHTMARE
if ($normal == '' && $hard == '' && $nightmare == '')
{
}
else
{
$template->assign_block_vars('8m_bonethrasher', array(
'VAR1' => $row['pf_guild_name'],
'VAR2' => $normal,
'VAR3' => $hard,
'VAR4' => $nightmare,
));
}
}
$db->sql_freeresult($result);
不是100%肯定你的要价,但看看'包括()' – 2012-03-03 00:32:23
嗯,我会基本上不得不创建另外60个这样的代码块,我将要改变的是向另一个老板提交“pf_kp_em_no_bonethr”这一行,所以我想知道是否会有一种方法可以回收代码,这将阻止我不得不复制那封锁了60次 – 2012-03-03 00:41:41
嗯,函数+数组? – Synetech 2012-03-03 00:58:07