VB.net查询Datagrid视图

Question

我需要在datagrid中显示值而不是id。 我有两个表 表1，具有empid，receivedbyid，releasebyid，这个ID仅指表2 ，其中表2具有id，name。

我需要在datagrid上显示Table1尊敬的NAME不是ID。 前表1 ID的被1,3,3 表2的数据是，1 - NAME1，2 - 名称2，3-NAME3

输出应该是，

Name1, Name3, Name3 

Answer 1

对于C＃

  StringBuilder sb = new StringBuilder(); 
     sb.appendLine(" select b.name as EmpName,c.Name as Receivedby,d.name as releasedby from table1 as a "); 
     sb.appendLine(" inner join table2 as b on a.empid = b.id "); 
     sb.appendLine(" inner join table2 as c on a.receivedbyid = b.id "); 
     sb.appendLine(" inner join table2 as d on a.releasebyid = b.id "); 

     SqlConnection conn = new SqlConnection(MyConString); 
     SqlCommand cmd = new SqlCommand(sb.tostring(), conn); 
       conn.Open(); 
       DataTable dataTable = new DataTable(); 
       SqlDataAdapter da = new SqlDataAdapter(cmd); 

       da.Fill(dataTable); 


       GridVIew.DataSource = dataTable; 
       GridVIew.DataBind(); 

For vb

Dim sb As New StringBuilder() 
sb.appendLine(" select b.name as EmpName,c.Name as Receivedby,d.name as releasedby from table1 as a ") 
sb.appendLine(" inner join table2 as b on a.empid = b.id ") 
sb.appendLine(" inner join table2 as c on a.receivedbyid = b.id ") 
sb.appendLine(" inner join table2 as d on a.releasebyid = b.id ") 

Dim conn As New SqlConnection(MyConString) 
Dim cmd As New SqlCommand(sb.tostring(), conn) 
conn.Open() 
Dim dataTable As New DataTable() 
Dim da As New SqlDataAdapter(cmd) 

da.Fill(dataTable) 


GridVIew.DataSource = dataTable 
GridVIew.DataBind() 

此代码将帮助您。