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的财产,我努力理解如何laravel作品,我有一个非常困难的时间与它Laravel试图让非对象
型号 - user.php的用户模型
<?php
use Illuminate\Auth\UserInterface;
use Illuminate\Auth\Reminders\RemindableInterface;
class User extends Eloquent implements UserInterface, RemindableInterface {
protected $fillable = array('email' , 'username' , 'password', 'code');
/**
* The database table used by the model.
*
* @var string
*/
protected $table = 'users';
/**
* The attributes excluded from the model's JSON form.
*
* @var array
*/
protected $hidden = array('password');
public function Characters()
{
return $this->hasMany('Character');
}
/**
* Get the unique identifier for the user.
*
* @return mixed
*/
public function getAuthIdentifier()
{
return $this->getKey();
}
/**
* Get the password for the user.
*
* @return string
*/
public function getAuthPassword()
{
return $this->password;
}
/**
* Get the e-mail address where password reminders are sent.
*
* @return string
*/
public function getReminderEmail()
{
return $this->email;
}
}
模式 - Character.php人物模型
<?php
class Character extends Eloquent {
protected $table = 'characters';
protected $fillable = array('lord_id','char_name', 'char_dynasty', 'picture');
public function user()
{
return $this->belongsTo('User');
}
public function Titles()
{
return $this->hasMany('Title');
}
}
?>
routes.php文件
Route::group(array('prefix' => 'user'), function()
{
Route::get("/{user}", array(
'as' => 'user-profile',
'uses' => '[email protected]'));
});
ProfileController.php
<?php
class ProfileController extends BaseController{
public function user($user) {
$user = User::where('username', '=', Session::get('theuser'));
$char = DB::table('characters')
->join('users', function($join)
{
$join->on('users.id', '=', 'characters.user_id')
->where('characters.id', '=', 'characters.lord_id');
})
->get();
if($user->count()) {
$user = $user->first();
return View::make('layout.profile')
->with('user', $user)
->with('char', $char);
}
return App::abort(404);
}
}
在我的代码,我会重定向到这条路线有以下:
return Redirect::route('user-profile', Session::get('theuser'));
在视图我只想做: 欢迎回来,{{$用户 - >用户名}},你的主要字符是{{$ char-> char_name}}
我的问题是,我会收到此错误:尝试获取我的视图中的非对象的属性。我相信它指的是$ char-> char_name。出了什么问题?我很难理解Laravel。我不知道为什么。提前致谢!
我怎样才能将消息发送到视图? –
当我在我的视图中编写此代码时,仍然收到相同的错误:欢迎回来,{{$ user-> username}},您的主角是{{$ user-> Character-> char_name}} –