Bash Pass数组功能

Question

我不清楚我在这里做错了什么，或者是否存在某种类型的bash问题？

我声明了一些静态sting数组，并交互地构建了另一个字符串值数组，并将其全部传递给bash函数。我在函数本身内部看到数组值的腐败。

add_firewall_rich_rules() { 
    node_ips="${1}" 
    swarm_tcp_ports="${2}" 
    swarm_udp_ports="${3}" 
    echo "in: ${node_ips[@]}" 
    echo "in: ${swarm_tcp_ports[@]}" 
    echo "in: ${swarm_udp_ports[@]}" 
    for ip in "${node_ips[@]}" 
    do 
     for tcp_port in "${swarm_tcp_ports[@]}" 
     do 
       rule="'rule family=\"ipv4\" source address=\"$ip\" port protocol=\"tcp\" port=\"$tcp_port\" accept'" 
       cmd="firewall-cmd --permanent --zone=public --add-rich-rule=$rule" 
       echo "$cmd" 
     done 
     for udp_port in "${swarm_udp_ports[@]}" 
     do 
       rule="'rule family=\"ipv4\" source address=\"$ip\" port protocol=\"udp\" port=\"$udp_port\" accept'" 
       cmd="firewall-cmd --permanent --zone=public --add-rich-rule=$rule" 
       echo "$cmd" 
     done 
    done 
} 

declare -a swarm_tcp_ports=('2377' '7946' '4789' '8500' '4000') 
declare -a swarm_udp_ports=('2377' '7946' '4789') 
declare -a node_ips=() 
echo "init: ${node_ips[@]}" 
echo "init: ${swarm_tcp_ports[@]}" 
echo "init: ${swarm_udp_ports[@]}" 
node_ip="" 
last_node_ip="" 
while read -e -p "Enter ip of additional node in the cluster (hit enter twice to stop adding values): " -i "`echo $node_ip |sed 's/[^.]*$//'`" node_ip; do 
    if [ "$node_ip" == "$last_node_ip" ]; then 
    break 
    fi 
    if [[ $node_ip =~ ^[0-9]+\.[0-9]+\.[0-9]+\.[0-9]+$ ]]; then 
    node_ips=("${node_ips[@]}" $node_ip) 
    else 
    echo "hit return again to stop adding values" 
    fi 
    last_node_ip=$node_ip 
    echo "${swarm_tcp_ports[@]}" 
done 

if [ "${#node_ips[@]}" -gt 0 ]; then 
    echo "out: ${node_ips[@]}" 
    echo "out: ${swarm_tcp_ports[@]}" 
    echo "out: ${swarm_udp_ports[@]}" 
    add_firewall_rich_rules ${node_ips[@]} ${swarm_tcp_ports[@]} ${swarm_udp_ports[@]} 
fi 

从终端：

# ./firewall_add_rich_rule.sh 
init: 
init: 2377 7946 4789 8500 4000 
init: 2377 7946 4789 
Enter ip of additional node in the cluster (hit enter twice to stop adding values): 192.168.1.105 
2377 7946 4789 8500 4000 
Enter ip of additional node in the cluster (hit enter twice to stop adding values): 192.168.1.106 
2377 7946 4789 8500 4000 
Enter ip of additional node in the cluster (hit enter twice to stop adding values): 192.168.1. 
hit return again to stop adding values 
2377 7946 4789 8500 4000 
Enter ip of additional node in the cluster (hit enter twice to stop adding values): 192.168.1. 
out: 192.168.1.105 192.168.1.106 
out: 2377 7946 4789 8500 4000 
out: 2377 7946 4789 
in: 192.168.1.105 192.168.1.106 
in: 192.168.1.106 7946 4789 8500 4000 
in: 2377 7946 4789 
firewall-cmd --permanent --zone=public --add-rich-rule='rule family="ipv4" source address="192.168.1.105" port protocol="tcp" port="192.168.1.106" accept' 
firewall-cmd --permanent --zone=public --add-rich-rule='rule family="ipv4" source address="192.168.1.105" port protocol="tcp" port="7946" accept' 
firewall-cmd --permanent --zone=public --add-rich-rule='rule family="ipv4" source address="192.168.1.105" port protocol="tcp" port="4789" accept' 
firewall-cmd --permanent --zone=public --add-rich-rule='rule family="ipv4" source address="192.168.1.105" port protocol="tcp" port="8500" accept' 
firewall-cmd --permanent --zone=public --add-rich-rule='rule family="ipv4" source address="192.168.1.105" port protocol="tcp" port="4000" accept' 
firewall-cmd --permanent --zone=public --add-rich-rule='rule family="ipv4" source address="192.168.1.105" port protocol="udp" port="2377" accept' 
firewall-cmd --permanent --zone=public --add-rich-rule='rule family="ipv4" source address="192.168.1.105" port protocol="udp" port="7946" accept' 
firewall-cmd --permanent --zone=public --add-rich-rule='rule family="ipv4" source address="192.168.1.105" port protocol="udp" port="4789" accept' 
firewall-cmd --permanent --zone=public --add-rich-rule='rule family="ipv4" source address="192.168.1.106" port protocol="tcp" port="192.168.1.106" accept' 
firewall-cmd --permanent --zone=public --add-rich-rule='rule family="ipv4" source address="192.168.1.106" port protocol="tcp" port="7946" accept' 
firewall-cmd --permanent --zone=public --add-rich-rule='rule family="ipv4" source address="192.168.1.106" port protocol="tcp" port="4789" accept' 
firewall-cmd --permanent --zone=public --add-rich-rule='rule family="ipv4" source address="192.168.1.106" port protocol="tcp" port="8500" accept' 
firewall-cmd --permanent --zone=public --add-rich-rule='rule family="ipv4" source address="192.168.1.106" port protocol="tcp" port="4000" accept' 
firewall-cmd --permanent --zone=public --add-rich-rule='rule family="ipv4" source address="192.168.1.106" port protocol="udp" port="2377" accept' 
firewall-cmd --permanent --zone=public --add-rich-rule='rule family="ipv4" source address="192.168.1.106" port protocol="udp" port="7946" accept' 
firewall-cmd --permanent --zone=public --add-rich-rule='rule family="ipv4" source address="192.168.1.106" port protocol="udp" port="4789" accept' 

好像从传递到函数的第一阵列的第一个元素被替换该函数调用后经过下一个阵列的所述第一元件由（和我有时会注意到下一个数组，但这次不是）。

Answer 1

当您将数组传递给函数时，它将展开值。

arr1=("1" "2" "3") 
arr2=("a" "b" "c") 

someFunc "${arr1[@]}" "${arr2[@]}" 

#same as someFunc "1" "2" "3" "a" "b" "c" "d" 

所以在你的函数，你应该采取的阵列的名称，而不是扩大他们和声明为您的函数中的新数组。

arrayTest(){ 
    declare -a localArr1=("${!1}") 
    declare -a localArr2=("${!2}") 

    //process arrays 
} 

arr1=("1" "2" "3") 
arr2=("a" "b" "c") 

arrayTest "arr1[@]" "arr2[@]"