2014-03-14 70 views

回答

0

您需要的阵列内爆,以逗号分隔字符串

$variables_imploded = implode(",",$variable); 

"SELECT * 
FROM software_capability 
where software_capability_id IN 
(".$variables_imploded.")"; 
+0

由于abhik其工作。 – Senthilkumar

+0

非常欢迎您! –

+0

@Senthilkumar请接受这个答案,因为它会被标记为已解决 –

0

使用JOIN或破灭

$variables_joins = join(',',$variable); 

SELECT * FROM software_capability where software_capability_id IN ($variables_joins);