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我试图解码json回调。在php中解码json并创建变量
JSON的代码被发布到callback.php - 这里是JSON的一个例子：
{
"order": {
"id": "5RTQNACF",
"created_at": "2012-12-09T21:23:41-08:00",
"status": "completed",
"total_btc": {
"cents": 100000000,
"currency_iso": "BTC"
},
"total_native": {
"cents": 1253,
"currency_iso": "USD"
},
"custom": "order1234",
"receive_address": "1NhwPYPgoPwr5hynRAsto5ZgEcw1LzM3My",
"button": {
"type": "buy_now",
"name": "Alpaca Socks",
"description": "The ultimate in lightweight footwear",
"id": "5d37a3b61914d6d0ad15b5135d80c19f"
},
"transaction": {
"id": "514f18b7a5ea3d630a00000f",
"hash": "4a5e1e4baab89f3a32518a88c31bc87f618f76673e2cc77ab2127b7afdeda33b",
"confirmations": 0
},
"customer": {
"email": "[email protected]",
"shipping_address": [
"John Smith",
"123 Main St.",
"Springfield, OR 97477",
"United States"
]
}
}
}
我可以附和JSON，并得到如下回应：如果我
{"order""id":null,"created_at":null,"status":"completed","total_btc":{"cents":100000000,"currency_iso":"BTC"},"total_native":{"cents":83433,"currency_iso":"USD"},"custom":"123456789","receive_address":"1A2qsxGHo9KjtWBTnAopTwUiBQf2w6yRNr","button":{"type":"buy_now","name":"Test Item","description":null,"id":null},"transaction":{"id":"52d064b59eeb59985e00002c","hash":"4a5e1e4baab89f3a32518a88c31bc87f618f76673e2cc77ab2127b7afdeda33b","confirmations":0}}}
然而尝试解码json使用以下内容：
$array = json_decode($jsonString, true);
echo $array;
我得到以下响应：“200阵列”
我希望能够将每个json参数都变成一个php变量。
如果你想看到它的字符串输出，不要'echo'数组'var_dump（）'或'print_r（）'。 –
可能重复[在PHP中从json回调中获取POST数据]（http://stackoverflow.com/questions/21052500/get-post-data-from-a-json-callback-in-php） – mario
而那200不是由发布的代码生成的，但是我猜测脚本中的其他地方会回应HTTP请求的结果并获得200响应代码。 –