5
这是一个搜索函数,它返回每个成员注册的最近一年。使用查询生成器的Laravel嵌套连接查询
我知道它与DB :: raw()调用。但无法让它与查询构建器一起工作。
工作代码:
$query = DB::table('membership as m');
$query->join(
DB::raw(
'(SELECT my.*
FROM membership_years my
INNER JOIN (
SELECT member_id,MAX(membership_year) AS max_my
FROM membership_years
GROUP BY member_id
) my2
ON my.member_id = my2.member_id
AND my.membership_year = my2.max_my
) my'
)
,'m.id','=','my.member_id');
我在查询生成器代码尝试:
$query = DB::table('membership as m');
$query->join('membership_years as my',
function($j1){
$j1->join('membership_years as my2',
function($j2){
$j2->where('my.membership_year','=','MAX(my2.membership_year)')
->on('my.member_id','=','my2.member_id');
}
)->on('m.id','=','my.member_id');
}
);
产生的错误是:
调用未定义的方法照亮\数据库\ Query \ JoinClause :: join()
我不确定这是否是因为$j2
无法再访问连接方法?
原MySQL查询:
SELECT my.membership_year,m.*
FROM membership AS m
INNER JOIN
(
SELECT my1.*
FROM membership_years my1
INNER JOIN
(
SELECT member_id,MAX(membership_year) AS max_my
FROM membership_years
GROUP BY member_id
) my2
ON my1.member_id = my2.member_id
AND my1.membership_year = my2.max_my
) my
ON m.id = my.member_id
ORDER BY m.id ASC