根据另一列ID选择列的最大数量

Question

我想要在具有属性teamID，salary，yearID的表中每年获得最高工资。不应该很难吗？这里是我的查询：

SELECT teamID, MAX(tS.teamSalary), yearID 
FROM 
    (SELECT 
     teamID, 
     sum(salary) AS teamSalary, 
     yearID 
    FROM salaries 
    GROUP BY teamID, yearID) tS 
GROUP BY yearID; 

内部查询工作得很好，但外一个只是报告每个组的第一个teamID。我究竟做错了什么？

Inner query output: 
A 1 2000 
B 1 2000 
C 2 2000 
A 2 2001 
B 3 2001 
A 2 2002 
B 2 2002 

Full query output: 
A 1 2000 
A 2 2001 
A 2 2002 

Desired output: 
C 2 2000 
B 3 2001 
A 2 2002 

Answer 1

首先你maxSalary攀升，那么你得到的额外信息：

SELECT teamID, salary, yearID 
    FROM salaries 
    JOIN 
    (SELECT MAX(salary) AS maxSalary, 
      yearID 
     FROM salaries 
    GROUP BY yearID) tS 
    ON ts.yearID = salaries.yearID 
    AND ts.maxSalary = salaries.salary 

编辑：不知道，如果你想要一些当年最高的薪水，那么它所属的团队，或如果你想要团队和年份的最高工资。第二个选项在这里：

SELECT MAX(salary) AS maxSalary, yearID, teamID 
    FROM salaries 
GROUP BY yearID, teamID