在Django中,我需要过滤数据并显示结果。例如过滤数据并按no排序显示结果。的职位
Company3(20)
Company1(12)
Company2(3)
这里“公司1,Company2的,公司3”是公司名称和括号内“20,12,3”都没有。由特定公司发布的工作。
models.py
class User(models.Model):
first_name= forms.CharField(max_length=30,widget=forms.TextInput())
last_name = forms.CharField(max_length=30,widget=forms.TextInput())
username = forms.CharField(max_length=30,widget=forms.TextInput())
email = forms.EmailField(widget=forms.TextInput())
password = forms.CharField(widget=forms.PasswordInput())
companyname = forms.CharField(max_length=30,widget=forms.TextInput())
class jobs(models.Model):
emp = models.ForeignKey(User, unique=False)
title = models.CharField(max_length=30)
referencecode = models.CharField(max_length=30)
jobsummary = models.TextField()
jobdetails = models.TextField()
key_skills = models.CharField(max_length=30)
我试着给views.py就像
def search_result(request):
details=User.objects.filter(jobs__isnull=False).select_related()
return render_to_response('searchresult.html', {'details': details})
templates
<ul>
{% for d1 in details %}
<li>{{ d1.companyname }}({{ d1.count }})</li>
{% endfor %}
</ul>
给一些想法,像上面
它显示相同的输出 – Karthik 2013-04-23 05:17:34
输出 公司1() 公司1() Company2的() 我张贴2个作业为公司1和1 Company2的 – Karthik 2013-04-23 05:19:13
喔,它应该是'{{d1.jobs_set.count}}',我建议误'd1.emp_set '。 – Rohan 2013-04-23 06:17:07