其中预计参数1是mysqli的MySQL连接错误

Question

警告（！）：mysqli_select_db（）预计参数1是在C中给出的mysqli，字符串：\瓦帕\ WWW \ go4shop \上线的config.php 7

我在下面的代码中得到了上面的错误。请人帮我

<?php 
$dbhost = "localhost"; 
$dbuser = "root"; 
$dbpassword = "1234"; 
$dbdatabase = "go4shop"; $c``onfig_basedir = "http://localhost/go4shop/"; 
$config_sitename = "Go4Shop"; 
$db = mysqli_connect($dbhost, $dbuser, $dbpassword); mysqli_select_db($dbdatabase, $db); 
?> 

Answer 1

LINKNAME第一，那么数据库名称...

mysqli_select_db (mysqli $link , string $dbname) 

或在您的情况

mysqli_select_db($db, $dbdatabase)