与最小值选择多列

Question

示例模式：

id val1 val2 val3 val4 val5 mid 
1 5  6 7 1 4 1 
4 7  8 5 9 5 1 
5 4  1 4 2 7 2 
7 3  2 8 7 2 1 

这里是我尝试，但此查询只返回1的所有值列：

SELECT id, MIN(val1), MIN(val2), MIN(val3), MIN(val4), MIN(val5) FROM table WHERE mid=1 

我想要的结果是（为每个VAL列选择ID，作为分分钟（valx），其中中间= 1）：

id min 
7 3 
7 2 
4 5 
1 1 
7 2 

一个注意：列的量可高达50（valx其中x是数字从1到50）。

Answer 1

select id, val1 from table where val1=(select min(val1) from table where mid=1) and mid=1 
union all 
select id, val2 from table where val2=(select min(val2) from table where mid=1) and mid=1 
union all 
select id, val3 from table where val3=(select min(val3) from table where mid=1) and mid=1 
union all 
select id, val4 from table where val4=(select min(val4) from table where mid=1) and mid=1 
union all 
select id, val5 from table where val5=(select min(val5) from table where mid=1) and mid=1 

Answer 2

使用LEAST()功能...

select id, least(val1, val2, <etc>) 
from myTable 
where mid=1 

Answer 3

SELECT id, MIN(val1), MIN(val2), MIN(val3), MIN(val4), MIN(val5) 
FROM table 
WHERE mid=1 
GROUP by id 

Answer 4

如果我正确理解你的问题，我希望它会帮助你

SELECT id, MIN(minimum) as minimum FROM (
SELECT id, val1 As minimum FROM table where mid=1 
UNION ALL 
SELECT id, val2 As minimum FROM table where mid=1 
UNION ALL 
SELECT id, val3 As minimum FROM table where mid=1 
union All 
SELECT id, val4 As minimum FROM table where mid=1 
union ALL 
SELECT id, val5 As minimum FROM table where mid=1 
) As minvalue 
GROUP BY id 

Answer 5

SELECT id, minimum 
FROM 
    (SELECT MIN(Val1) as minimum FROM TableName WHERE Mid = 1) v1 
    INNER JOIN TableName t1 
    ON v1.minimum = t1.Val1 
    AND t1.Mid = 1 

UNION ALL 

SELECT id, minimum 
FROM 
    (SELECT MIN(Val2) as minimum FROM TableName WHERE Mid = 1) v2 
    INNER JOIN TableName t2 
    ON v2.minimum = t2.Val2 
    AND t2.Mid = 1 

UNION ALL 

SELECT id, minimum 
FROM 
    (SELECT MIN(Val3) as minimum FROM TableName WHERE Mid = 1) v3 
    INNER JOIN TableName t3 
    ON v3.minimum = t3.Val3 
    AND t3.Mid = 1 

UNION ALL 

SELECT id, minimum 
FROM 
    (SELECT MIN(Val4) as minimum FROM TableName WHERE Mid = 1) v4 
    INNER JOIN TableName t4 
    ON v4.minimum = t4.Val4 
    AND t4.Mid = 1 

UNION ALL 

SELECT id, minimum 
FROM 
    (SELECT MIN(Val5) as minimum FROM TableName WHERE Mid = 1) v5 
    INNER JOIN TableName t5 
    ON v5.minimum = t5.Val5 
    AND t5.Mid = 1 

这仅仅是一个讨厌讨厌查询和情况，但我想清楚你想要什么。如果你改进叙述，你可能会得到比这更好的答案。

下面是我把你想要的结果和叙述的意思。

查找Mid = 1的每列的最小值，然后查找与该最小值相关的ID。以上的结果是：

id minimum 
7 3 
7 2 
4 5 
1 1 
7 2 

注4 5对你确实有5 4 5，但将是VAL3最小值因为表示图4是其中中间= 2。因此，对于值5的ID是4。 ...

Answer 6

对不起，以前的答案，没有看到你的结果。 我希望这会给你结果。

;with cte as(
    Select a.ID 
     , t.Val 
     , ROW_NUMBER() over(partition by a.id order by t.ColNo) as ColNo 
    From @TABLE as a 
    Outer apply (Values (1,Val1), (2,Val2),(3,Val3),(4,Val4), (5,Val5)) t(ColNo,Val) 
    Where a.MID=1 
) 
, cte2 as( 
    Select ColNo, MIN(val) as MinVal 
    From cte 
    Group by ColNo 
) 
    Select a.ID, a.Val from cte as a 
    Inner join cte2 as b on a.ColNo=b.ColNo and a.Val=b.MinVal 
    Order by a.ColNo