我已经写了这个查询来显示某个员工在特定日期(如果他来了)的总工作时间和加班时间。我希望如果某个特定日期的人的INtime和OutTime是空的,则在他的银泰,外出时间,总工作时间,加班时间等00:00放置。星期天显然没有InTime和OutTime,那么它应该在时间列中显示00:00。 注意:只有在提及InTIme的情况下才会输入日期,否则不会输入DateVisited。将数据添加到列
例如
EmplID EmplName ShiftID intime Outtime totalworking overtime dateVisited
0000001 John S001 00:00 00:00 00:00: 00:00 2013-12-01
查询:
with times as (
SELECT t1.EmplID
, t3.EmplName
, min(t1.RecTime) AS InTime
, max(t2.RecTime) AS [TimeOut]
, t4.ShiftId as ShiftID
, t4.StAtdTime as ShStartTime
, t4.EndAtdTime as ShEndTime
, cast(min(t1.RecTime) as datetime) AS InTimeSub
, cast(max(t2.RecTime) as datetime) AS TimeOutSub
, t1.RecDate AS [DateVisited]
FROM AtdRecord t1
INNER JOIN
AtdRecord t2
ON t1.EmplID = t2.EmplID
AND t1.RecDate = t2.RecDate
AND t1.RecTime < t2.RecTime
inner join
HrEmployee t3
ON t3.EmplID = t1.EmplID
inner join AtdShiftSect t4
ON t3.ShiftId = t4.ShiftId
group by
t1.EmplID
, t3.EmplName
, t1.RecDate
, t4.ShiftId
, t4.StAtdTime
, t4.EndAtdTime
)
SELECT
EmplID
,EmplName
,ShiftId As ShiftID
,InTime
,[TimeOut]
,convert(char(5),cast([TimeOutSub] - InTimeSub as time), 108) TotalWorkingTime
,[DateVisited]
,CASE WHEN [InTime] IS NOT NULL AND [TimeOut] IS NOT NULL THEN
CONVERT(char(5),CASE WHEN CAST([TimeOutSub] AS DATETIME) >= ShEndTime And ShiftID = 'S002' Then LEFT(CONVERT(varchar(12), DATEADD(ms, DATEDIFF(ms, CAST(ShEndTime AS DATETIME),CAST([TimeOutSub] AS DATETIME)),0), 108),5)
WHEN CAST([TimeOutSub] AS DATETIME) >= ShEndTime And ShiftID = 'S001' Then LEFT(CONVERT(varchar(12), DATEADD(ms, DATEDIFF(ms, CAST(ShEndTime AS DATETIME), CAST([TimeOutSub] AS DATETIME)),0), 108),5)
ELSE '00:00' END, 108)
ELSE 'ABSENT' END AS OverTime
FROM times order by EmplID, ShiftID, DateVisited
你已经有一个'CASE'语句,这里有什么问题? –
问题是假期我应该提及00:00在时间段 – PreciseTech
对不起,也许我只是需要更多的咖啡。我们怎么知道这是假期? –