Android - 动作列表视图

Question

我正在创建我的第一个应用程序，我想在listview中创建动作。

我已经创建列表视图，但是当我点击的观点，即特定的图标应该降落到一个新的页面，在这里我可以在你的ListFragment缩进Web视图

public class HomeFragment extends ListFragment { 

// Array of strings storing country names 
String[] title = new String[] { 
     "About Us", 
     "Attend class", 
     "Events", 
     "What's hot", 
     "Social Networks" 


};  

// Array of integers points to images stored in /res/drawable/ 
int[] img = new int[]{ 
     R.drawable.about, 
     R.drawable.clas, 
     R.drawable.cale, 
     R.drawable.hot1, 
     R.drawable.socil, 

}; 

// Array of strings to store currencies 
String[] description = new String[]{ 
    "Our Story", 
    "vlrn.in", 
    "Update Your Schedule", 
    "Need a Hot cake ? ", 
    "Connect with us", 

}; 


@Override 
public View onCreateView(LayoutInflater inflater, ViewGroup container,Bundle savedInstanceState) { 

    // Each row in the list stores country name, currency and flag 
    List<HashMap<String,String>> aList = new ArrayList<HashMap<String,String>>();   

    for(int i=0;i<5;i++){ 
     HashMap<String, String> hm = new HashMap<String,String>(); 
     hm.put("txt", "" + title[i]); 
     hm.put("cur","" + description[i]); 
     hm.put("flag", Integer.toString(img[i]));    
     aList.add(hm);   
    } 

    // Keys used in Hashmap 
    String[] from = { "flag","txt","cur" }; 

    // Ids of views in listview_layout 
    int[] to = { R.id.flag,R.id.txt,R.id.cur};   

    // Instantiating an adapter to store each items 
    // R.layout.listview_layout defines the layout of each item 
    SimpleAdapter adapter = new SimpleAdapter(getActivity().getBaseContext(), aList, R.layout.fragment_home, from, to);  

    setListAdapter(adapter); 

    return super.onCreateView(inflater, container, savedInstanceState);  
} 

} 

Answer 1

覆盖onListItemClick，那里你可以访问点击项目数据并将其显示在新页面上。

public void onListItemClick (ListView l, View v, int position, long id) { 
    // do it here 
}