listview setItemChecked无法正常工作

我遇到了由合并游标填充的listview问题。我在我的应用程序中有一个按钮来选择我的列表视图中的所有条目。按下按钮时调用的函数如下：listview setItemChecked无法正常工作

private void selectAllEntries() { 
    int numberOfItemsInList = listView.getCount(); 
    for (int i = 0; i < numberOfItemsInList; i++) { 
     this.listView.setItemChecked(i, true); 
    } 
}

问题是，并非所有条目最后都会被检查。确实很奇怪。经过一些测试后，我注意到如果我在mergecursor中有10个条目（5个来自游标a，5个来自游标b），那么如果我只在前5个元素上使用setItemChecked，那么一切正常（这5个条目会被检查）。如果我在最后5个元素上再次使用setItemchecked，一切正常（光标b的条目被检查），但是如果我对两个游标的元素使用setItemChecked，那么获取检查的元素的最大数量是光标a中元素的数量（在我们的例子中为5），偏移量为（我想设置的项目数 - 光标a中的项目数）。我会写下几个例子，因为这是一个非常奇怪的行为。

Example 1: 
element 0 (from cursor a, unchecked) 
element 1 (from cursor a, unchecked) 
element 2 (from cursor a, unchecked) 
element 3 (from cursor a, unchecked) 
element 4 (from cursor a, unchecked) 
element 5 (from cursor b, unchecked) 
element 6 (from cursor b, unchecked) 
element 7 (from cursor b, unchecked) 
element 8 (from cursor b, unchecked) 
element 9 (from cursor b, unchecked) 

setItemChecked(0,true); 
setItemChecked(1,true); 
setItemChecked(2,true); 
setItemChecked(3,true); 
setItemChecked(4,true); 

Results: 

element 0 (from cursor a, checked) 
element 1 (from cursor a, checked) 
element 2 (from cursor a, checked) 
element 3 (from cursor a, checked) 
element 4 (from cursor a, checked) 
element 5 (from cursor b, unchecked) 
element 6 (from cursor b, unchecked) 
element 7 (from cursor b, unchecked) 
element 8 (from cursor b, unchecked) 
element 9 (from cursor b, unchecked) 

Example 2: 
element 0 (from cursor a, unchecked) 
element 1 (from cursor a, unchecked) 
element 2 (from cursor a, unchecked) 
element 3 (from cursor a, unchecked) 
element 4 (from cursor a, unchecked) 
element 5 (from cursor b, unchecked) 
element 6 (from cursor b, unchecked) 
element 7 (from cursor b, unchecked) 
element 8 (from cursor b, unchecked) 
element 9 (from cursor b, unchecked) 

setItemChecked(5,true); 
setItemChecked(6,true); 
setItemChecked(7,true); 
setItemChecked(8,true); 
setItemChecked(9,true); 

results: 

element 0 (from cursor a, unchecked) 
element 1 (from cursor a, unchecked) 
element 2 (from cursor a, unchecked) 
element 3 (from cursor a, unchecked) 
element 4 (from cursor a, unchecked) 
element 5 (from cursor b, checked) 
element 6 (from cursor b, checked) 
element 7 (from cursor b, checked) 
element 8 (from cursor b, checked) 
element 9 (from cursor b, checked) 

Example 3: 
element 0 (from cursor a, unchecked) 
element 1 (from cursor a, unchecked) 
element 2 (from cursor a, unchecked) 
element 3 (from cursor a, unchecked) 
element 4 (from cursor a, unchecked) 
element 5 (from cursor b, unchecked) 
element 6 (from cursor b, unchecked) 
element 7 (from cursor b, unchecked) 
element 8 (from cursor b, unchecked) 
element 9 (from cursor b, unchecked) 

setItemChecked(0,true); 
setItemChecked(1,true); 
setItemChecked(2,true); 
setItemChecked(3,true); 
setItemChecked(4,true); 
setItemChecked(5,true); 

results in 

element 0 (from cursor a, unchecked) 
element 1 (from cursor a, checked) 
element 2 (from cursor a, checked) 
element 3 (from cursor a, checked) 
element 4 (from cursor a, checked) 
element 5 (from cursor b, checked) 
element 6 (from cursor b, unchecked) 
element 7 (from cursor b, unchecked) 
element 8 (from cursor b, unchecked) 
element 9 (from cursor b, unchecked) 


Example 4: 
element 0 (from cursor a, unchecked) 
element 1 (from cursor a, unchecked) 
element 2 (from cursor a, unchecked) 
element 3 (from cursor a, unchecked) 
element 4 (from cursor a, unchecked) 
element 5 (from cursor b, unchecked) 
element 6 (from cursor b, unchecked) 
element 7 (from cursor b, unchecked) 
element 8 (from cursor b, unchecked) 
element 9 (from cursor b, unchecked) 

setItemChecked(0,true); 
setItemChecked(1,true); 
setItemChecked(2,true); 
setItemChecked(3,true); 
setItemChecked(4,true); 
setItemChecked(5,true); 
setItemChecked(6,true); 

results: 

element 0 (from cursor a, unchecked) 
element 1 (from cursor a, unchecked) 
element 2 (from cursor a, checked) 
element 3 (from cursor a, checked) 
element 4 (from cursor a, checked) 
element 5 (from cursor b, checked) 
element 6 (from cursor b, checked) 
element 7 (from cursor b, unchecked) 
element 8 (from cursor b, unchecked) 
element 9 (from cursor b, unchecked) 


Example 5: 
element 0 (from cursor a, unchecked) 
element 1 (from cursor a, unchecked) 
element 2 (from cursor a, unchecked) 
element 3 (from cursor a, unchecked) 
element 4 (from cursor a, unchecked) 
element 5 (from cursor b, unchecked) 
element 6 (from cursor b, unchecked) 
element 7 (from cursor b, unchecked) 
element 8 (from cursor b, unchecked) 
element 9 (from cursor b, unchecked) 

setItemChecked(0,true); 
setItemChecked(1,true); 
setItemChecked(2,true); 
setItemChecked(3,true); 
setItemChecked(4,true); 
setItemChecked(5,true); 
setItemChecked(6,true); 
setItemChecked(7,true); 

results: 

element 0 (from cursor a, unchecked) 
element 1 (from cursor a, unchecked) 
element 2 (from cursor a, unchecked) 
element 3 (from cursor a, checked) 
element 4 (from cursor a, checked) 
element 5 (from cursor b, checked) 
element 6 (from cursor b, checked) 
element 7 (from cursor b, checked) 
element 8 (from cursor b, unchecked) 
element 9 (from cursor b, unchecked)

我现在用的是

 listView.setChoiceMode(ListView.CHOICE_MODE_MULTIPLE);

和

notifyDataSetChanged()

也没有帮助。有什么帮助吗？

作为一个侧面说明，

listView.getCount();

总是返回视图

来源

2013-09-01 sakis kaliakoudas

CursorAdapter使用数据库中的_id列来标识行，而AbsListView使用该值来跟踪哪些行被检查。这听起来像你的MergeCursor可能会返回重复的ID，例如，游标A中第一行的_id值与游标B中第一行的_id相同。是这种情况吗？ – alanv

就是这样，谢谢！看到我的评论如下 –

为alanv说，条目数正确“的CursorAdapter使用_id列从您的数据库，以确定行，并且AbsListView使用这个值来跟踪哪些行被检查，这听起来像你的MergeCursor可能会返回重复的ID，例如，游标A中第一行的_id值与游标B中第一行的_id相同。那个案子？“

就是这样。改变光标后，以提供不同ID的所有工作好但是：

合并光标是其他光标的串联，不应该合并光标能够用相同的ID从不同子来处理游标（例如通过在内部创建新的ID）。
查看合并游标的所有结果，并与它们进行交互（点击它们）工作正常，所以我希望检查它们以及它是否正常工作？

来源

2013-09-01 11:46:10

listview setItemChecked无法正常工作

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