将if语句添加到while循环

Question

此代码的前提是要求输入名称，最多尝试3次。

password = 'correct' 
attempts = 3 
password = input ('Guess the password: ') 
while password != 'correct' and attempts >= 2: 
    input ('Try again: ') 
    attempts = attempts-1 
if password == 'correct':    #Where the problems begin 
    print ('Well done') 

我只能输入正确的密码，第一次尝试返回'做得好'。在另外两次尝试中，它会返回为“再次尝试”。如果输入任何尝试，我怎样才能让它恢复得很好？

Answer 1

如果您想再试一次，那么您需要捕获该值。

password = input ('Try again: ') 

否则，while循环不会停止。

此外，Python有而-一样，它可以帮助您解决问题

while password != 'correct' and attempts >= 2: 
    password = input ('Try again: ') 
    attempts = attempts-1 
else: 
    print('while loop done') 
    if password == 'correct':    #Where the problems begin 
     print ('Well done') 

---

或者

attempts = 3 
password = input('Enter pass: ') 
while attempts > 0: 
    if password == 'correct': 
     break 
    password = input ('Try again: ') 
    attempts = attempts-1 
if attempts > 0 and password == 'correct': 
    print ('Well done') 

Answer 2

attempts = 3 
while attempts > 1: 
    password = input("Guess password") 
    if password == "correct" and attempts > 2: 
     print("Well done") 
     break 
    else: 
     print("try again") 
    attempts = attempts - 1 

Answer 3

这是一个有趣的方式来做到这一点，而不是使用计数器时，您可以创建一个包含三个元素的列表，并且while测试可确保仍有元素：

password,wrong,right = 'nice',['Wrong']*3,['you got it!'] 
while len(wrong)>0 and len(right)>0: 
    right.pop() if input('guess:')==password else wrong.pop()