1
我想学习指针,我得到这个错误。我是否需要更改头文件类Request?为什么我会收到这样的错误?类型错误和指针混淆
cannot convert `req' from type `Request' to type `Request *'
错误是发生在论文线:
//Store necessary information in a Request object for each request.
Request req(url, request, 1);
Request *reqq = req; //req points to the object
list->Append(reqq);
代码:
void
ClientThread(int request)
{
const int sz = 50;
char url[sz];
FILE *fp = fopen("url.txt", "r");
if (!fp)
printf(" Cannot open file url.txt!\n");
else {
int pos = 0;
char c = getc(fp);
while (c != EOF || pos == sz - 1) {
if (c == '\n') {
url[pos] = '\0';
serve(url);
pos = 0;
//Store necessary information in a Request object for each request.
Request req(url, request, 1);
Request *reqq = req; //req points to the object
list->Append(reqq);
}
else {
url[pos++] = c;
}
c = getc(fp);
}
fclose(fp);
}
}
我request.h文件包括以下内容:
class Request
{
public:
//constructor intializes request type
Request(char *u, int rqtID, int rqtrID);
char *url;
int requestID;
int requesterID;
}
'req'是'Request'。 'reqq'是一个指向'Request'的指针。从一个到另一个没有转换。 – juanchopanza 2014-09-25 21:56:00
运算符'&'的地址用于将对象转换为指针:'&req'。 – 2014-09-25 21:56:10
@MarkRansom:'&'操作符不会将*对象转换为指针。它会产生一个指向对象地址的指针值。 – 2014-09-25 22:09:32