我正在研究laravel中的第一个项目,现在我执行搜索功能,但是,我正在做一个涉及多个左连接的查询,并且在搜索时会返回一些冗余信息。在laravel中执行此查询的最佳方式是什么?
相关的表是这四和查询如下:
$searchData = ProfessionalDetail::select('u.id as user_id','u.first_name','u.last_name','u.profile_pic','c.name as city_name','professional_details.avg_ratings')
->join('users as u' , 'u.id', '=' ,'professional_details.user_id')
->join('user_speciality as us' , 'us.user_id', '=' ,'professional_details.user_id')
->join('specialities as sp' , 'sp.id', '=' ,'us.speciality_id')
->join('cities as c' , 'c.id', '=' ,'professional_details.city_id')
->join('users_roles as ur' , 'ur.user_id', '=' ,'professional_details.user_id')
->where(function ($q2) use ($name) {
$q2->where('u.first_name' , 'like', '%' . $name . '%')
->orWhere('u.last_name','like', '%'.$name.'%')
->orWhere('u.first_name','like',$name.'%');
->orWhere('sp.name','like',$name.'%');
})
->where('ur.role_id' ,'=' , 2)
->paginate($num_per_page);
return $searchData;[![demo][1]][1]
我试了一下,是用户都列出来,通过名称或专业(这是一个医生页面),当专业准备好时,一切进展顺利。但是当我想按用户列出时,有左连接'user_speciality'和'professional_details'。这使用户无数次返回给我。
例如:
public function testApi(Request $request)
{
$users = ProfessionalDetail::searchByNameAndSpe("joshi", 10);
$i = 0;
if ($users) {
foreach ($users as $key => $value) {
$response["result"][] = $value;
$response["total"] = $i++;
}
} else {
return "error";
}
return $response;
}
返回:
{"result":[{"user_id":204,"first_name":"Joshi","last_name":"Mohit","profile_pic":"1495436016.jpg","name":"Skin Specialist","city_name":"Pune","avg_ratings":"0.00"},{"user_id":204,"first_name":"Joshi","last_name":"Mohit","profile_pic":"1495436016.jpg","name":"Heart Specialist","city_name":"Pune","avg_ratings":"0.00"},{"user_id":204,"first_name":"Joshi","last_name":"Mohit","profile_pic":"1495436016.jpg","name":"ENT Specialist","city_name":"Pune","avg_ratings":"0.00"},{"user_id":204,"first_name":"Joshi","last_name":"Mohit","profile_pic":"1495436016.jpg","name":"Kidney Specialist","city_name":"Pune","avg_ratings":"0.00"},{"user_id":204,"first_name":"Joshi","last_name":"Mohit","profile_pic":"1495436016.jpg","name":"Eye Specialist","city_name":"Pune","avg_ratings":"0.00"}],"total":4}
乔希只能注册一次,但是我知道他会因关系“多对多”,因为他返回了无数次拥有几个专业。现在
,要得到它的专业和用户的名称进行搜索,我所知道的唯一的办法就是使用左加入,我想办法给信息分离将被处理的信息但是II想知道这是否可以在查询中解决,因为我对SQL不太了解,如果有什么办法,我会非常感激,因为它会为我节省很多调试步骤所有的信息。
每个模型的方法
UserSpeciality表
public function users() {
return $this->belongsToMany('App\User', 'user_speciality', 'speciality_id', 'user_id');
}
用户
public function userSpeciality() {
return $this->belongsToMany('App\Speciality','user_speciality', 'user_id', 'speciality_id');
}
专业
public function users() {
return $this->belongsToMany('App\User', 'user_speciality', 'user_id', 'speciality_id');
}
ProfesionalDetail表
public function user(){
return $this->belongsTo("App\User");
}
你有模型建立这些表? –
如果和每一个都有其相应的关系方法, 我修改了帖子并添加了他们 –