mysql_real_escape_string（）：拒绝用户'root'@'localhost'的访问（使用密码：否）

Question

我发现这个错误在我的错误日志中重复出现，我认为它导致内存泄漏导致我的网站停机。

PHP Warning: mysql_query(): Access denied for user 'root'@'localhost' (using password: NO) in /mysql.class.php on line 74 

PHP Warning: mysql_query(): A link to the server could not be established in /mysql.class.php on line 74 

PHP Warning: mysql_real_escape_string(): Access denied for user 'root'@'localhost' (using password: NO) in /functions.php on line 380 

PHP Warning: mysql_real_escape_string(): A link to the server could not be established in /functions.php on line 380 

PHP Warning: mysql_query(): Access denied for user 'root'@'localhost' (using password: NO) in /mysql.class.php on line 100 

PHP Warning: mysql_query(): A link to the server could not be established in /home/glo/mysql.class.php on line 100 

在mysql.class.php，这里是从管线72中的代码，以104

function &execute() { 
    $query = $this->read(); 
    **$res = mysql_query($query);** // line 74 

    if ($res || mysql_errno() == 1062) { 
     return $res; 
    } 
    $mysql_error = mysql_error(); 
    $mysql_errno = mysql_errno(); 

    // If debug_backtrace() is available, we can find exactly where the query was called from 
    if (function_exists("debug_backtrace")) { 
     $bt = debug_backtrace(); 

     $i = 1; 

     if ($bt[$i]["function"] == "SQL_Query_exec_cached" || $bt[$i]["function"] == "get_row_count_cached" || $bt[$i]["function"] == "get_row_count") 
      $i++; 

     $line = $bt[$i]["line"]; 
     $file = str_replace(getcwd().DIRECTORY_SEPARATOR, "", $bt[$i]["file"]); 
     $msg = "Database Error in $file on line $line: $mysql_error. Query was: $query."; 
    } else { 
     $file = str_replace(getcwd().DIRECTORY_SEPARATOR, "", $_SERVER["SCRIPT_FILENAME"]); 
     $msg = "Database Error in $file: $mysql_error. Query was: $query"; 
    } 

    mysql_query("INSERT INTO `sqlerr` (`txt`, `time`) 
       **VALUES (".sqlesc($msg).", '".get_date_time()."')");** // line 100 

    if (function_exists('show_error_msg')) 
     show_error_msg("Database Error", "Database Error. Please report this to an Admin.", 1); 
} 

在的functions.php这里是代码

// MySQL escaping 
function sqlesc($x) { 
if (!is_numeric($x)) { 
    $x = "'".mysql_real_escape_string($x)."'"; // Line 380 
} 
return $x; 
} 

为我的连接的代码是

function_exists("mysql_connect") or die("MySQL support not available."); 

@mysql_connect($mysql_host, $mysql_user, $mysql_pass) or die('DATABASE: mysql_connect: ' . mysql_error()); 
@mysql_select_db($mysql_db) or die('DATABASE: mysql_select_db: ' . mysql_error()); 

任何帮助t o调试这些错误是非常感谢....

Answer 1

看起来这里的问题是连接超出了函数的范围，所以mysql函数试图创建一个没有任何凭证的新连接。

尝试将连接分配给一个变量，然后在函数中将其作为全局调用。

$conn = @mysql_connect($mysql_host, $mysql_user, $mysql_pass); 

function &execute() { 
    global $conn; 
    $query = $this->read(); 
    $res = mysql_query($query, $conn); 
    .... 

您可以在这里PHP手册了解更多有关范围http://www.php.net/manual/en/language.variables.scope.php

注意：使用全局变量是不建议 - 这将是更好的做法是使用更OO的方法，创建在连接你的MySQL的类如：

public function connect ($host, $user, $pass) { 
    $this->connection = mysql_connect($host, $user, $pass); 
} 

function &execute() { 
    $query = $this->read(); 
    $res = mysql_query($query, $this->connection); 
    .... 

，然后使用这样的连接

$db = new MysqlClassName(); 
$db->connect($mysql_host, $mysql_user, $mysql_pass); 

Answer 2

显示错误可能被关闭在php.ini或您的apache配置文件。在页面顶部

<?php 
      error_reporting(E_ALL); 
      ini_set('display_errors', 1); 
    ?> 

写上面的脚本和u会看到错误消息：

您可以在脚本中打开它。 您应该在php错误日志中看到相同的消息。