在Java中将十六进制字符串转换为ASCII码

Question

我希望这不是一个愚蠢的问题，我已经查看了谷歌搜索结果的5个不同页面，但一直未能找到任何关于此的信息。

我需要做的是转换包含所有的十六进制字符转换为ASCII例如

String fileName = 

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 

每次我见过的方式使得它好像你必须把它变成一个数组中第一个字符串。有没有办法循环通过每两个并将其转换？

Answer 1

只需使用一个for循环都要经过每对夫妇的字符串中的字符，将它们转换为字符，然后捶字符在一个字符串生成器的结尾：

public static void main(String[] args) { 
    String hex = "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"; 
    StringBuilder output = new StringBuilder(); 
    for (int i = 0; i < hex.length(); i+=2) { 
     String str = hex.substring(i, i+2); 
     output.append((char)Integer.parseInt(str, 16)); 
    } 
    System.out.println(output); 
} 

这给了几行开始执行以下操作：

的uTorrent \完成\ nfsuc_ost_by_mustang \摆-9000 Miles.mp3

嗯... :-)

Answer 2

退房Convert a string representation of a hex dump to a byte array using Java?

不顾编码等，你可以做new String (hexStringToByteArray("75546..."));

Answer 3

所以，据我所知，你需要拉出连续对十六进制数字，然后解码2个数字的十六进制数，并采取相应的字符：

String s = "..."; 
StringBuilder sb = new StringBuilder(s.length()/2); 
for (int i = 0; i < s.length(); i+=2) { 
    String hex = "" + s.charAt(i) + s.charAt(i+1); 
    int ival = Integer.parseInt(hex, 16); 
    sb.append((char) ival); 
} 
String string = sb.toString(); 

Answer 4

String hexToAscii(String s) { 
    int n = s.length(); 
    StringBuilder sb = new StringBuilder(n/2); 
    for (int i = 0; i < n; i += 2) { 
    char a = s.charAt(i); 
    char b = s.charAt(i + 1); 
    sb.append((char) ((hexToInt(a) << 4) | hexToInt(b))); 
    } 
    return sb.toString(); 
} 

private static int hexToInt(char ch) { 
    if ('a' <= ch && ch <= 'f') { return ch - 'a' + 10; } 
    if ('A' <= ch && ch <= 'F') { return ch - 'A' + 10; } 
    if ('0' <= ch && ch <= '9') { return ch - '0'; } 
    throw new IllegalArgumentException(String.valueOf(ch)); 
} 

Answer 5

//%%%%%%%%%%%%%%%%%%%%%% HEX to ASCII %%%%%%%%%%%%%%%%%%%%%% 
public String convertHexToString(String hex){ 

String ascii=""; 
String str; 

// Convert hex string to "even" length 
int rmd,length; 
length=hex.length(); 
rmd =length % 2; 
if(rmd==1) 
hex = "0"+hex; 

    // split into two characters 
    for(int i=0; i<hex.length()-1; i+=2){ 

     //split the hex into pairs 
     String pair = hex.substring(i, (i + 2)); 
     //convert hex to decimal 
     int dec = Integer.parseInt(pair, 16); 
     str=CheckCode(dec); 
     ascii=ascii+" "+str; 
    } 
    return ascii; 
} 

public String CheckCode(int dec){ 
    String str; 

      //convert the decimal to character 
     str = Character.toString((char) dec); 

     if(dec<32 || dec>126 && dec<161) 
      str="n/a"; 
    return str; 
} 

Answer 6

最容易的方法它javax.xml.bind.DatatypeConverter：

String hex = "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"; 
    byte[] s = DatatypeConverter.parseHexBinary(hex); 
    System.out.println(new String(s)); 

Answer 7

这种情况，我有一个十六进制数据格式转换成int数组，我想将它们转换的字符串。

int[] encodeHex = new int[] { 0x48, 0x65, 0x6c, 0x6c, 0x6f }; // Hello encode 
for (int i = 0; i < encodeHex.length; i++) { 
    System.out.print((char) (encodeHex[i])); 
}