我有一个脚本验证表单(使用jQuery Validate),然后提交数据。它目前运行良好,但现在我需要添加一个复选框,并且我不清楚如何使用jQuery/ajax提交值。我是否需要包含诸如$('#checkBox').attr('checked');
之类的内容?如果是这样,我如何将它传递给ajax?jquery验证 - 点击“提交”检查复选框
此外,当我点击“提交”,没有完成表格,复选框自动检查自己。这是为什么发生?
的jquery:
<script>
$(document).ready(function(){
$("#formid").validate({
rules: {
name: "required",
email: {
required: true,
email: true
},
mobile: {
required: true,
minlength: 10
},
news: {
required: false,
}
},
messages: {
name: "Please enter your name",
email: "Please enter a valid email address",
mobile: "Please enter your mobile number"
},
submitHandler: function() {
var name = $('#name').attr('value');
var email = $('#email').attr('value');
var mobile = $('#mobile').attr('value');
var news = $('#news').attr('value');
$.ajax({
type: "POST",
url: "ajax.php",
data: $("#formid").serialize(),
success: function(){
$('form#formid').hide();
$('div.success').fadeIn();
}
});
return false;
}
});
});
</script>
形式:
<form id="formid" method="post">
<fieldset>
<div>
<label for="name">Name</label>
<input type="text" id="name" name="name" class="required" />
</div>
<div>
<label for="email">Email</label>
<input type="text" id="email" name="email" class="required" />
</div>
<div>
<label for="mobile">Mobile</label>
<input type="text" id="mobile" name="mobile" class="required" />
</div>
<label for="news"><p>Please don’t send me ongoing news</p>
<input type="checkbox" id="news" name="news" value="No" />
<label for="submit1" id="submit"><span> </span>
<input id="submit1" type="submit" name="submit" value="Submit"/>
</label>
</fieldset>
</form>
它的确如此。辉煌:-)非常感谢!多么愚蠢的错误...... – circey 2012-08-01 02:31:06
@circey我们都做到了;) – 2012-08-01 02:32:07