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有以下PHP:获取与mysqli的数据库条目
<?php
session_start();
$conn = mysqli_connect("localhost", "test", "", "test");
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$sql = "SELECT status FROM updates";
if ($result = mysqli_query($conn, $sql)) {
while ($row = mysqli_fetch_row($result)) {
echo '<div class="statusRow">' . "Status: " . $row['status'] . '</div>';
}
mysqli_free_result($result);
}
mysqli_close($conn);
?>
以上没有返回所期望的“地位”输入,只是空白。不知道我在这里错过了什么?
基本的错误检查和显示。 – rtfm
@KevinP输出是“状态:” –
将$ row ['status']更改为$ row [0] –