我是Haskell的新手,我必须实现一个简单的tic tac脚趾游戏。它不需要AI。从矩阵中替换元素(Haskell)
我需要更新我的矩阵,但我不知道该怎么做。
这里是我的蹩脚的代码:
import Array
table :: Array (Int, Int) Char
table = array ((1,1),(3,3))
[
((1,1), '0'), ((1,2), '0'), ((1,3), '0'),
((2,1), '0'), ((2,2), '0'), ((2,3), '0'),
((3,1), '0'), ((3,2), '0'), ((3,3), '0')
]
getGrid :: IO()
getGrid = do
print (elems table)
putStr "Escolha o numero da casa em que deseja jogar: "
n <- getChar
if isValid n == (0, 0) then
getGrid
else if (table ! isValid n) == '0' then do
putStr "\nProssiga: "
getPlayer n
else do
putStr "\nCasa ocupada, tente novamente: "
getGrid
getPlayer :: Char -> IO()
getPlayer n = do
putStr "\nJogador X: "
j <- getChar
if (j /= 'b' && j /= 'B' && j /= 'p' && j /= 'P') then do
getPlayer n
else do
(table ! isValid n) = j
getGrid
isValid :: Char -> (Int,Int)
isValid n
| n == '0' = (1, 1)
| n == '1' = (1, 2)
| n == '2' = (1, 3)
| n == '3' = (2, 1)
| n == '4' = (2, 2)
| n == '5' = (2, 3)
| n == '6' = (3, 1)
| n == '7' = (3, 2)
| n == '8' = (3, 3)
| otherwise = (0, 0)
我不知道该怎么做,以取代其他值...的0:/
非常感谢!我会尝试,后来我发布结果。 :) – Celso