2014-02-11 85 views
1

我有一个bisectionMethod函数,它接受一个函数作为其参数之一。对于方法的意图和目的,它接受的函数参数只有一个正在优化的参数。但是,我想将任何类型的函数(包含任意数量的参数)传递给bisectionMethod函数。我在bisectionMethod函数中使用了一个指针函数作为参数,但它要求我精确指定有多少个参数进入该指针函数。什么是最好的解决方法?将一个函数(可变参数数量!)作为参数传递

例如,我试图做这样的事情:

double bisectionMethod(double xMinimum, double xMaximum, double maxError, double (*rootFunc)(double)) 
{ 
    ... 
    return ret; 
} 

double foo1(double x1, double y1){return x1 * y1;} 
double foo2(double x2, double y2, double z2){return x2 * y2 * z2;} 

int main(){ 

// I want to first be able to set y1 in foo1. 
// Then I want to solve for x1 
bisectionMethod(5, 250, 0.1, foo1(x1)); 

// I want to also be able to use bisectionMethod with foo2 
// I want to first be able to set x1, and y1 in foo2. 
// Then I want to solve for z1 
bisectionMethod(5, 250, 0.1, foo1(z1)); 

return 0; 

} 

希望的例子是有道理的。我知道这有点奇怪。任何帮助,将不胜感激。谢谢!

+0

只需使用一个推导类型参数和'的std :: bind'。 – chris

+0

C++ 11 lambda如何? –

+0

或'boost:bind' – Mine

回答

0
#include <functional> 
using namespace std; 
using namespace std::placeholders; 

double bisectionMethod(double xMinimum, double xMaximum, double maxError, function<double (double)>) 
{ 
    ... 
    return ret; 
} 

double foo1(double x1, double y1){return x1 * y1;} 
double foo2(double x2, double y2, double z2){return x2 * y2 * z2;} 

int main(){ 

// I want to first be able to set y1 in foo1. 
// Then I want to solve for x1 
bisectionMethod(5, 250, 0.1, std::bind(foo1, _1, 1.0)); 

// I want to also be able to use bisectionMethod with foo2 
// I want to first be able to set x1, and y1 in foo2. 
// Then I want to solve for z1 
bisectionMethod(5, 250, 0.1, std::bind(foo2, _1, 1.0, 2.0)); 

return 0; 

} 

这适用于C++ 11.使用的boost ::绑定的C++ 98

+0

请注意,占位符被置于错误的位置...... – Mine

0

增压版本:

#include <boost/bind.hpp> 
#include <boost/function.hpp> 

double bisectionMethod(double xMinimum, double xMaximum, double maxError, boost::function<double(double)>) 
{ 
    ... 
    return 0; 
} 

double foo1(double x1, double y1){return x1 * y1;} 
double foo2(double x2, double y2, double z2){return x2 * y2 * z2;} 

int main(){ 

    // I want to first be able to set y1 in foo1. 
    // Then I want to solve for x1 
    bisectionMethod(5, 250, 0.1, boost::bind(foo1, _1, y1)); 

    // I want to also be able to use bisectionMethod with foo2 
    // I want to first be able to set x1, and y1 in foo2. 
    // Then I want to solve for z1 
    bisectionMethod(5, 250, 0.1, boost::bind(foo2, x1, y1, _1)); 

    return 0; 

} 
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