如何从android中的光标检索对应于特定字段的数据？

数据库类如何从android中的光标检索对应于特定字段的数据？

public boolean Permissions(String modulename) { 
    int createable, updateable; 
    Cursor cursor = db.rawQuery("select * from " + "moduleDesc" + " where " 
      + "name" + "='" + modulename + "'", null); 
    if (cursor.getCount() > 0); 
     { 
     createable = cursor.getInt(cursor.getColumnIndex("createable")); 
     updateable = cursor.getInt(cursor.getColumnIndex("updateable")); 
     cursor.close(); 
    } 
    if ((createable == 1) && (updateable == 1)) { 
     return true; 

    } else { 
     return false; 
    } 
}

是我得到的错误是可创建cursor.getInt(cursor.getColumnIndex("createable")); cursorindexoutofbounds虽然光标是有一些价值还是它给这个错误！ thanx提前

来源

2012-07-27 Android Fanatic

在取数据之前，您需要先移动光标到第一条记录。 – 2012-07-27 12:27:14

有了适当的光标闭合。

public boolean Permissions(String modulename) { 
    Cursor cursor = db.rawQuery("select * from " + "moduleDesc" + " where " 
      + "name" + "='" + modulename + "'", null); 
    if (cursor != null) { 
     try { 
      if (cursor.moveToFirst()) { 
       int createable = cursor.getInt(cursor.getColumnIndex("createable")); 
       int updateable = cursor.getInt(cursor.getColumnIndex("updateable")); 
       return (createable == 1) && (updateable == 1); 
      } 
     } finally { 
      cursor.close(); 
     } 
    } 
    return false; 
}

来源

2012-07-27 12:22:07 biegleux

不是：

if (cursor.getCount() > 0) { 
     //Code here 
    }

使用

if (cursor.moveToFirst()) { 
     //Code here 
    }

这可能会解决你的问题。

来源

2012-07-27 12:17:53

thanxxx它的工作 – 2012-07-27 12:22:53

如果它解决了你的问题，你应该接受这个答案:) – 2012-07-27 12:28:58

Try this solution 

public boolean Permissions(String modulename) { 
int createable, updateable; 
Cursor cursor = db.rawQuery("select * from " + "moduleDesc" + " where " 
     + "name" + "='" + modulename + "'", null); 
if (cursor.getCount() > 0); 
    { 
    cursor.MoveToFirst();//use this if cursor count is 1 else use while loop 
    //while (cursor.MoveToNext){ 
    createable = cursor.getInt(cursor.getColumnIndex("createable")); 
    updateable = cursor.getInt(cursor.getColumnIndex("updateable")); 
    //} 
    cursor.close(); 
} 
if ((createable == 1) && (updateable == 1)) { 
    return true; 

} else { 
    return false; 
}

}

来源

2012-07-27 12:19:56 Archana

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