将元素从子列表中移除到列表中

Question

我们通过列表和子列表来查找列表。 我想在列表中删除列表中的第一个子列表。

这里是我想要的一个例子：

removeSubList([3,2,3,4,5,3],[3]) [2,3,4,5,3] 
removeSubList([2,3,4,5,3,4],[3,4]) [2,5,3,4] 
removeSubList([3,2,3,4,7],[3,7]) [2,3,4] 
removeSubList([3,2,3,4,5,3],[]) [3,2,3,4,5,3] 
removeSubList([],[3,7]) [] 
removeSubList(null,[3,7]) null 
removeSubList([3,2,3,4,5,3],null) [3,2,3,4,5,3] 

这里是我的代码我试过，但它不工作...

public class RemovePositionList<E> { 

/** 
* Returns in "list" the previous content of "list" after removing "subList" if it is present in "list" 
* 
* @param list  (input/output) The list where search and remove the first occurrence of "subList" 
* @param subList (input)   The sub list to search within "list" 
*/ 

public void removeSubList(PositionList<E> list,PositionList<E> subList) { 
    Position<E> cursor = list.first(); 
    Position<E> cursor2 = subList.first(); 
    while(cursor != null && cursor2 != null){ //comprobamos que ningun elemento es null 
     if(cursor.element().equals(cursor2)){ 
      list.remove(cursor); 
     } 
     else{ 
      list.next(cursor); 
      list.next(cursor2); 
     } 
    } 
    } 
} 

感谢您的帮助...

Answer 1

我不知道如果我正确的，但我认为错误是在if()条件，而不是

if(cursor.element().equals(cursor2)) 

它不应该是

if(cursor.element().equals(cursor2.element())) 

.............. :)

Answer 2

我采取了不同的方法使您提供的样本输入。它适用于所有情况。

public static void main(String[] args) { 
    Integer listElements[] = {3,2,3,4,7}; 
    Integer subListElements[] = {3,7}; 

    List<Integer> list = new LinkedList<Integer>(Arrays.asList(listElements)); 
    List<Integer> subList = Arrays.asList(subListElements); 
    System.out.println(removeSubList(list, subList)); 
} 

private static List<Integer> removeSubList(List<Integer> list, List<Integer> subList){ 
    if(list == null || list.isEmpty() || subList == null){ 
     return list; 
    } 
    for(Integer item : subList){ 
     list.remove(item); 
    } 
    return list; 
}