C++接口继承

Question

我该如何在C++中进行这种派生？ （目前的例子不起作用）

struct IB 
    { 

    }; 

    struct IDerivedB : public IB 
    { 

    }; 

    struct IA 
    { 
    public: 
     virtual IB Foo(const string& type) = 0; 
    }; 

    struct IDerivedA : public IA 
    { 
    public: 
     virtual IDerivedB Foo(const string& type) override = 0; 
    }; 

谢谢！

Answer 1

返回类型的协方差仅适用于指针和引用，这应该工作：

struct IB 
{ 

}; 

struct IDerivedB : public IB 
{ 

}; 

struct IA 
{ 
public: 
    virtual IB* BuildPresenter(const string& type) = 0; 
}; 

struct IDerivedA : public IA 
{ 
public: 
    virtual IDerivedB* BuildPresenter(const string& type) override = 0; 
};