我有我正在为我的大学任务工作的以下代码。我被要求使用我正在使用的数组。我被要求使用for循环和if语句,我已经在做。我想出了下面的代码:检查输入与Java中的字符串数组中的项目
class HardwareStore2 {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.printf("%55s", "**WELCOME TO THE HARDWARE STORE**\n");
System.out.printf("%55s", "=================================\n");
String [] codes = {"G22", "K13", "S21", "I30"};
String [] description = {"STICKY Construction Glue", "CAR-LO Key Ring", "SCREW-DUP Screwy Screws", "LET-IT-RAIN Padlock"};
List<String> codeList = Arrays.asList(codes);
String output = "";
int i = 1000;
String [] userCode = new String[i];
char dolSymb = '$';
int [] pricesAndTax = {10989, 5655, 1099, 4005, 20};
int [] weight = {};
int [] userQuantity = {1};
int [] userPrice = new int[i];
int userStickyPrice = 0;
int userKeyringPrice = 0;
int userScrewyPrice = 0;
int userPadlockPrice = 0;
int userPreWithTax = 0;
int userTotal = 0;
int userPreTotal = 0;
int userShipping = 0;
System.out.printf("%-10s%-40s%-15s%-10s\n", "CODE", "DESCRIPTION", "WEIGHT", "PRICE\n");
System.out.printf("%-10s%-55s%s%d.%02d\n", codes[0], description[0], dolSymb, pricesAndTax[0]/100, pricesAndTax[0]%100);
System.out.printf("%-10s%-55s%s%d.%02d\n", codes[1], description[1], dolSymb, pricesAndTax[1]/100, pricesAndTax[1]%100);
System.out.printf("%-10s%-55s%s%d.%02d\n", codes[2], description[2], dolSymb, pricesAndTax[2]/100, pricesAndTax[2]%100);
System.out.printf("%-10s%-55s%s%d.%02d\n", codes[3], description[3], dolSymb, pricesAndTax[3]/100, pricesAndTax[3]%100);
System.out.println("PLEASE ENTER YOUR ORDER:");
System.out.print("NAME: ");
String username = in.nextLine();
System.out.print("ADDRESS Line 1: ");
String address1 = in.nextLine();
System.out.print("ADDRESS Line 2: ");
String address2 = in.nextLine();
System.out.print("POSTAL CODE: ");
String postalcode = in.nextLine();
for (i = 0;; i++) {
System.out.print("CODE (X to QUIT):");
userCode[i] = in.nextLine();
if (userCode[i].equalsIgnoreCase("x")) {
break;
}
System.out.print("QUANTITY: ");
userQuantity[i] = in.nextInt();
in.nextLine();
if (userCode[i].equalsIgnoreCase(codes[0])) {
userStickyPrice += userQuantity[i]*pricesAndTax[0];
}
else if (userCode[i].equalsIgnoreCase(codes[1])) {
userKeyringPrice += userQuantity[i]*pricesAndTax[1];
}
else if (userCode[i].equalsIgnoreCase(codes[2])) {
userScrewyPrice += userQuantity[i]*pricesAndTax[2];
}
else if (userCode[i].equalsIgnoreCase(codes[3])) {
userPadlockPrice += userQuantity[i]*pricesAndTax[3];
}
else if (!codeList.contains(userCode)) {
i = i - 1;
}
}
}
}
现在,一切都以百万IFS无缝协作,并别人的,但我想知道是否有替换所有的if-else-if语句wirht方式一个或两个做这样的事情:
if (userCode[i].contains(codes[0], codes[1], codes[2], codes[3] {}
或者,也许更好的东西,如:
if (userCode.contains(any.one.item.in.codeList) {
then.get.the.price.of.that.item.and.do.item.specific.operations
}
请让我知道,如果这个问题不够清楚。再次,这是一个大学作业,所以我会很感激解释。
如果“地图”更好,我确实有时间和精力去寻找那个方向。由于我是一个Java新手,你是指Hashmaps还是我完全在这里? –
@nickecarlo Hashmap是正确的,只要确保使用通用版本'Hashmap'(它可以提供更好的类型安全性)。您将定义一个局部变量,如下所示:Map codeToPriceAndTax = new HashMap ;'然后,您将在初始化期间向该映射添加代码/价格+税收对。在你的主循环中,你将使用'int priceAndTax = codeToPriceAndTax.get(userCode [i])'来通过代码循环价格+税。 –
dasblinkenlight
我会检查一下HashMap,谢谢。 –