Android文件上传不起作用

Question

嗨，我正在使用android。我创建了一个将文件上传到服务器的Android应用程序。我用下面的代码

http://androidexample.com/Upload_File_To_Server_-_Android_Example/index.php?view=article_discription&aid=83&aaid=106

但我不能上传我的文件。该应用程序显示上传开始，但没有文件上传到我的服务器位置。

Answer 1

 private class SendHttpRequestTask extends AsyncTask<String, Void, String> { 

     protected String doInBackground(String... params) { 

      String url = params[0]; 

      String param1 = params[1]; 

      String param2 = params[2]; 

     Bitmap b = BitmapFactory.decodeResource(UploadActivity.this.getResources(), R.drawable.logo); 



     ByteArrayOutputStream baos = new ByteArrayOutputStream(); 

     b.compress(CompressFormat.PNG, 0, baos); 



     try { 

      HttpClient client = new HttpClient(url); 

      client.connectForMultipart(); 

      client.addFormPart("param1", param1); 

      client.addFormPart("param2", param2); 

      client.addFilePart("file", "logo.png", baos.toByteArray()); 

      client.finishMultipart(); 

       String data = client.getResponse(); 

     } 

      catch(Throwable t) { 

      t.printStackTrace(); 

     } 



     return null; 

    } 



    @Override 

     protected void onPostExecute(String data) {   

     item.setActionView(null); 



     } 



    } 

Answer 2

public class save extends AsyncTask私有MyProgressDialog pDialog;

@Override 
    protected void onPreExecute() { 
     pDialog = new MyProgressDialog(Send_message.this); 
     pDialog.setCancelable(false); 
     pDialog.show(); 
     super.onPreExecute(); 
    } 

    @Override 
    protected String doInBackground(String... paramss) { 
     try { 
      String json = messagesend.sendmeesage("Your Url",params); 
      JSONObject jsonobject = new JSONObject(json); 
      String result = jsonobject.getString("result"); 
      if (result.equals("TRUE")) { 
       return "true"; 
      } 

      System.out.println("json is" + json); 
     } catch (ClientProtocolException e) { 
      e.printStackTrace(); 
     } catch (IOException e) { 
      e.printStackTrace(); 
     } catch (JSONException e) { 
      e.printStackTrace(); 
     } 
     return "false"; 
    } 

    @Override 
    protected void onPostExecute(String result) { 
     super.onPostExecute(result); 
     pDialog.dismiss(); 
    } 

} 

//发送文件 公共类messagesendwithhttp {

private String page; 

public String sendmeesage(String url, List<NameValuePair> nameValuePairs)throws ClientProtocolException, IOException 
{ 
    HttpClient httpClient = new DefaultHttpClient(); 
    HttpContext localContext = new BasicHttpContext(); 
    HttpPost httpPost = new HttpPost(url); 

    try { 
     MultipartEntity entity = new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE); 

     for (int index = 0; index < nameValuePairs.size(); index++) 
     { 
      if (index == 0 || index == 1) 
      { 
       // If the key equals to "image", we use FileBody to transfer 
       // the data 
       entity.addPart(nameValuePairs.get(index).getName(), new StringBody(nameValuePairs.get(index).getValue())); 
      } else { 
       // Normal string data 
       if(nameValuePairs.get(index).getValue().equals("") || nameValuePairs.get(index).getValue().toString().equals(null)) 
       { 
        entity.addPart(
          nameValuePairs.get(index).getName(), 
          new StringBody(nameValuePairs.get(index).getValue())); 
       } 
       else 
       { 
        entity.addPart(nameValuePairs.get(index).getName(), 
         new FileBody(new File(nameValuePairs.get(index) 
           .getValue()))); 
       } 

      } 
     } 


     httpPost.setEntity(entity); 
     HttpResponse response = httpClient.execute(httpPost, localContext); 
     HttpEntity resEntity = response.getEntity(); 
     if (resEntity != null) 
     { 
      page = EntityUtils.toString(resEntity); 
      System.out.println("PAGE :" + page); 
     } 
    } catch (IOException e) { 
     e.printStackTrace(); 
    } 
    return page; 
} 

}

enter code here 

Answer 3

可以使用httpmime库上传任何文件（图片，音频，视频等。 ） 请参考下面的代码。

enter code here 


    HttpClient httpClient = new DefaultHttpClient(); 
    HttpContext localContext = new BasicHttpContext(); 
    HttpPost postRequest = new HttpPost(your url); 
    MultipartEntity reqEntity = new MultipartEntity(
      HttpMultipartMode.BROWSER_COMPATIBLE); 

    try { 




     File file = new File(filename); 
     FileBody fileBody = new FileBody(file); 
     reqEntity.addPart("video_file", fileBody); 

     postRequest.setEntity(reqEntity); 
     HttpResponse response = httpClient.execute(postRequest, 
       localContext); 
     HttpEntity entity = response.getEntity(); 

     if (entity != null) { 
      // entity.consumeContent(); 
      BufferedReader rd = new BufferedReader(new InputStreamReader(
        entity.getContent())); 
      // Log.e("response", "response " + rd.toString()); 
      String line; 
      String result1 = ""; 
      while ((line = rd.readLine()) != null) { 
       result1 = result1 + line; 
       // Log.e("result", "line " + line); 




    } 
      // Log.e("result", "is " + result1); 
      return result1; 
     } 
    } catch (Exception e) { 
     return "Exception"; 
    } 
    return ""; 
} 

}

Answer 4

她是收发箱链接，上传到服务器程序文件 https://www.dropbox.com/s/qasj5o5mu3dq5ya/file_remote_send.zip 你刚刚更改娄代码

您的服务器发生在这里 字符串upLoadServerUri的URL =“http://example.com/UploadToServer.php&#8221 ;;

here uploaded_file id php base filename conn.setRequestProperty（“uploaded_file”，fileName）;

UploadToServer.php

<?php 

$file_path = “uploads/”; 

$file_path = $file_path . basename($_FILES['uploaded_file']['name']); 
if(move_uploaded_file($_FILES['uploaded_file']['tmp_name'], $file_path)) { 
echo “success”; 
} else{ 
echo “fail”; 
} 
?>