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我在Laravel中构建了一个API,并且正在使用自定义请求来验证入站数据。我的问题是,我不知道我如何“捕捉”验证错误来形成响应。Laravel在自定义请求中捕获验证异常
这是我到目前为止。
注册方法包裹在一个交易:
//Create User Request extends standard request. Handles Validation
public function __construct(CreateUserRequest $request){
$this->request = $request;
}
public function register()
{
try{
$array = DB::transaction(function(){
$email = $this->request->input('email');
$password = $this->request->input('password');
$companyName = $this->request->input('companyName');
$userName = $this->request->input('name');
$country = $this->request->input('country');
$company = Company::create([
'name' => $companyName,
'active'=>true,
'country_id'=>$country
]);
$user = User::create([
'company_id' => $company->id,
'name'=>'admin',
'email' => $email,
'password' => $password,
'active' =>true
]);
if(!$company || !$user)
{
throw new \Exception('User not created for account');
}
return compact('company', 'user');
});
$token = JWTAuth::fromUser($array['user']);
return Response::json(compact('token'));
}
catch(Exception $e)
{
return Response::json(['error' => $e->getMessage() ], HttpResponse::HTTP_CONFLICT);
}
}
形式请求如下所示:
class CreateUserRequest extends FormRequest
{
/**
* Determine if the user is authorized to make this request.
*
* @return bool
*/
public function authorize()
{
return true;
}
/**
* Get the validation rules that apply to the request.
*
* @return array
*/
public function rules()
{
return [
'email' => 'required|unique:users',
'password' => 'required',
'companyName' => 'required',
'name' => 'required',
'country' => 'required|numeric'
];
}
}
我的错误会自动回来了,这似乎是序列化到JSON
的messagebag对象{"email":["The email has already been taken."]}{"email":["The email has already been taken."]}
某处在那里我需要赶上例外,我在主控制器的旁边,但我已经使用自定义请求类来清理我的控制器了,我该怎么做?请注意,此控制器中已经捕获了异常,但似乎无法获取自定义请求中幕后引发的任何内容。
任何指针?我是否需要将验证移回控制器?还是有更干净的方法来做到这一点?
是啊,看起来像它会做的,我只是var_dumped $错误..任何想法为什么我在JSON中可能有两个错误? – Paul
只有重复的电子邮件?发送请求时不需要其他字段作为名称 –