在android中嵌套的Json解析

Question

我尝试响应嵌套的JSON数据解析，但我不能。下面的代码是我嵌套的json。

{ 
"Result": [ 
{ 
    "Stock": { 
    "ID": 1, 
    "Code": "sample string 2", 
    "SerialNo": "sample string 3", 
    "RFID": "sample string 4", 
    "PairCode": "sample string 5", 
    "Barcode": "sample string 6", 
    "Name": "sample string 7", 
    "Description": "sample string 8", 
    "Model": "sample string 9", 
    "CategoryId": 1, 
    "BrandId": 1, 
    "ClassificationId": 1 
    }, 
    "Division": { 
    "ID": 1, 
    "Name": "sample string 2", 
    "ParentID": 1, 
    "Path": "sample string 3" 
    }, 
    "User": { 
    "ID": 1, 
    "Name": "sample string 2", 
    "Username": "sample string 3", 
    "Password": "sample string 4" 
    } 
}, 
{ 
    "Stock": { 
    "ID": 1, 
    "Code": "sample string 2", 
    "SerialNo": "sample string 3", 
    "RFID": "sample string 4", 
    "PairCode": "sample string 5", 
    "Barcode": "sample string 6", 
    "Name": "sample string 7", 
    "Description": "sample string 8", 
    "Model": "sample string 9", 
    "CategoryId": 1, 
    "BrandId": 1, 
    "ClassificationId": 1 
    }, 
    "Division": { 
    "ID": 1, 
    "Name": "sample string 2", 
    "ParentID": 1, 
    "Path": "sample string 3" 
    }, 
    "User": { 
    "ID": 1, 
    "Name": "sample string 2", 
    "Username": "sample string 3", 
    "Password": "sample string 4" 
    } 
}, 
{ 
    "Stock": { 
    "ID": 1, 
    "Code": "sample string 2", 
    "SerialNo": "sample string 3", 
    "RFID": "sample string 4", 
    "PairCode": "sample string 5", 
    "Barcode": "sample string 6", 
    "Name": "sample string 7", 
    "Description": "sample string 8", 
    "Model": "sample string 9", 
    "CategoryId": 1, 
    "BrandId": 1, 
    "ClassificationId": 1 
    }, 
    "Division": { 
    "ID": 1, 
    "Name": "sample string 2", 
    "ParentID": 1, 
    "Path": "sample string 3" 
    }, 
    "User": { 
    "ID": 1, 
    "Name": "sample string 2", 
    "Username": "sample string 3", 
    "Password": "sample string 4" 
    } 
} 
], 
"RecordCount": 1 
} 

而且这是我的响应等级

public class ResultResponseModel<T>{ 

public int RecordCount; 

public T Result[]; 

public int getRecordCount() { 
    return RecordCount; 
} 

public void setRecordCount(int recordCount) { 
    RecordCount = recordCount; 
} 

public T[] getResult() { 
    return Result; 
} 

public void setResult(T[] result) { 
    Result = result; 
} 

}

其他类

public class ServiceStockDivisionUserModel { 

public ServiceStockDivisionUserModel() 
{ 
    Stock = new ServiceStockModel(); 

    Division = new ServiceDivisionModel(); 

    User = new ServiceUserModel(); 
} 

public ServiceStockModel Stock ; 

public ServiceDivisionModel Division ; 

public ServiceUserModel User ; 


public ServiceStockModel getStock() { 
    return Stock; 
} 

public void setStock(ServiceStockModel stock) { 
    Stock = stock; 
} 

public ServiceDivisionModel getDivision() { 
    return Division; 
} 

public void setDivision(ServiceDivisionModel division) { 
    Division = division; 
} 

public ServiceUserModel getUser() { 
    return User; 
} 

public void setUser(ServiceUserModel user) { 
    User = user; 
} 

}

我尝试播服务后，投我JSON ResultResponseModel tockDivisionUserMopdel来获取对象。但我无法施展，任何人都可以帮助我。谢谢。

我的理由：

JSONObject jsonObj = new JSONObject(responseModel.responseString); 

Gson gson = new Gson(); 

listResultResponseModel = gson.fromJson(String.valueOf(jsonObj), ResultResponseModel.class); 

Answer 1

在这里，您解析的实际响应您的服务器或其他资源获得

JSONArray result = response.optJSONArray("Result"); 
     int length = result.length(); 
     for(int i=0; i<length; i++){ 
      JSONObject userData = result.optJSONObject(i); 
      User user = new User(userData.optJSONObject("User")); 
      Division division = new Division(userData.optJSONObject("Division")); 
      Stock stock = new Stock(userData.optJSONObject("Stock")); 
     } 

User.java

public class User{ 

     private int ID; 
     private String Code; 
     //and other variables for UserData 


     public User(JSONObject userData) { 
      this.ID = userData.optInt("ID"); 
      this.Code = userData.optString("Code"); 
      //similar initializations for other variables 
     } 

     public int getID() { 
      return ID; 
     } 

     public String getCode() { 
      return Code; 
     } 
    } 

您需要为股票和分部创建类并在内部处理JSON的类似方法。

Answer 2

FullResponse model = new Gson().fromJson(JSON_STRING, FullResponse.class); 

作出这样的模式。

public class FullResponse{ 
    List<ResultResponse> Result; 
    int RecordCount; 

    //setter and getter 
} 

public class ResultResponse{ 
    StockResponse Stock; 
    DivisionResponse Division; 
    UserResponse User; 

    //setter and getter 
} 

public class StockResponse{ 
    int ID; 
    String Code; 
    .... 

    //getter 
} 

public class DivisionResponse{ 
    int ID; 
    String Name; 
    .... 

    //getter 
} 

public class UserResponse{ 
    int ID; 
    String Name; 
    .... 

    //getter 
} 

可选

如果你想检查是否您的JSON如果有效或不..

public boolean isJSONValid(String test) { 
    try { 
     new JSONObject(test); 
    } catch (JSONException ex) { 
     try { 
      new JSONArray(test); 
     } catch (JSONException ex1) { 
      return false; 
     } 
    } 
    return true; 
}