斯普利特和计算字数节点JS

Question

如果我有两个字符串像

s1 = "This is a foo bar sentence ." 
s2 = "This sentence is similar to a foo bar sentence ." 

我想分割的字符串，以这种格式

x1 = ["This":1,"is":1,"a":1,"bar":1,"sentence":1,"foo":1] 
x2 = ["This":1,"is":1,"a":1,"bar":1,"sentence":2,"similar":1,"to":1,"foo":1] 

它分割字符串文字和将它们计数到一对，其中每个字符串代表一个字，数字代表字符串中该字的计数。

Answer 1

删除标点符号，标准化空格，小写字母，在空格处拆分，使用循环将单词出现计入索引对象。

function countWords(sentence) { 
    var index = {}, 
     words = sentence 
       .replace(/[.,?!;()"'-]/g, " ") 
       .replace(/\s+/g, " ") 
       .toLowerCase() 
       .split(" "); 

    words.forEach(function (word) { 
     if (!(index.hasOwnProperty(word))) { 
      index[word] = 0; 
     } 
     index[word]++; 
    }); 

    return index; 
}