如何获得与最大ID行与表的条件在SQL Server

Question

我也有类似的这种

 
id-value-RowInid 
1-xy-1 
1-xx-2 
1-xz-3 
2-xx-1 
2-xr-2 
3-xq-1 
4-xa-1 
4-xc-2 
... 

我需要为这个表有类似的输出功能，以获得最大的RowInid在分离ID组的表

 
1-xz-3 
2-xr-2 
3-xq-1 
4-xc-2 
... 

Answer 1

不需要group by或最大所有

select id, value, rowinid from 
(select *, row_number() over (partition by id, order by rowinid desc) rn from yourtable) v 
where rn = 1 

Answer 2

你只需要使用 MAX(RowInid)与 GROUP BY Id, value

SELECT ID, VALUE, MAX(RowInid) FROM myTable GROUP BY ID, VALUE 

编辑：
当你更新你的问题，你可以使用子查询像这样得到value领域：

SELECT ID, VALUE, RowInid 
FROM myTable t1 WHERE RowInid = 
(
    SELECT MAX(RowInid) FROM myTable WHERE id = t1.id GROUP BY id 
) 
ORDER BY id ASC; 

您也可以实现用INNER JOIN这是这样的：

SELECT t2.ID, VALUE, t2.RowInid FROM myTable t1 
INNER JOIN 
(
    SELECT ID, MAX(RowInid) AS RowIniD FROM myTable GROUP BY ID 
) AS t2 
ON t1.ID = t2.ID AND t1.RowInid = t2.RowInid 
ORDER BY t1.ID ASC; 

See this SQLFiddle

在SQL Server中查看更多about GROUP BY和MAX。

Answer 3

与尝试，

使用子查询来获取身份证，价值和最大RowInid，

SELECT m1.[Id],m1.Value, m1.RowInid 
    FROM [Practice].[dbo].[myTable] m1 WHERE RowInid = (SELECT MAX(m2.RowInid) FROM [Practice].[dbo].[myTable] m2 WHERE M1.Id = m2.Id GROUP BY Id) 

上面的查询返回的结果，如： 4-XX-2 3-XX-1 2 -xx-2 1-XX-3

为升序这种用途中，

SELECT m1.[id],m1.Value, m1.RowInid 
FROM [Practice].[dbo].[myTable] m1 WHERE m1.RowInid = (SELECT MAX(m2.RowInid) FROM [Practice].[dbo].[myTable] m2 WHERE M2.id = m1.id GROUP BY id) ORDER BY m1.id ASC