从文本文件（Python）的

Question

char1= "P" 
length=5 
f = open("wl.txt", 'r') 

for line in f: 
if len(line)==length and line.rstrip() == char1: 
    z=Counter(line) 
    print z 

读取线specfic角色，我想只输出线，其中长度= 5和包含字符p.So远

f = open("wl.txt", 'r') 
    for line in f: 
    if len(line)==length :#This one only works with the length 
     z=Counter(line) 
     print z 

任何猜测别人？

Answer 1

您的问题是：

if len(line)==length and line.rstrip() == char1: 

如果行是5个字符长，然后除去尾随空格之后，你再对比看看它是否等于长度为1的串......“ABCDE '永远不会等于'p'，例如，如果你的行包含'p'，因为它不是5个字符，你的支票将永远不会运行...

我不确定你想要做什么Counter

更正后的代码是：

# note in capitals to indicate 'constants' 
LENGTH = 5 
CHAR = 'p' 

with open('wl.txt') as fin: 
    for line in fin: 
     # Check length *after* any trailing whitespace has been removed 
     # and that CHAR appears anywhere **in** the line 
     if len(line.rstrip()) == LENGTH and CHAR in line: 
      print 'match:', line