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以上为对象的DD()一个的结果,现在我所做的是
//$car is a object variable
$car->corporate_id = some_function($car->corporate_id);
$car->corporate_name = some_function($car->corporate_name);
$car->member_id = some_function($car->member_id);
而不是做上述方式,我怎么能达到像
$data = some_function($car);
//it will go through all $car properties and run the same validation
有人可以告诉我如何实现这一目标?
不,我期待al l对象属性通过调用一个函数来运行相同的验证函数,而不是像这样一个一个地执行 –