1
> str(b)
'data.frame': 2720 obs. of 3 variables:
$ State : chr "AL" "AL" "AL" "AL" ...
$ Hospital.Name: chr "SOUTHEAST ALABAMA MEDICAL CENTER" "MARSHALL MEDICAL
CENTER SOUTH" "ELIZA COFFEE MEMORIAL HOSPITAL" "ST VINCENT'S EAST" ...
$ heart attack : num 14.3 18.5 18.1 17.7 18 15.9 19.6 17.3 17.8 17.5 ...
以上是我的数据框。我想通过状态组,并通过各组内心脏发作进行排名,所以我的代码是这样的:r中的组内排名
c <- group_by(b,State) %>%
mutate(rank = order(order('heart attack')))
,但我得到了所有的排名列等于值1的结果:
> c
# A tibble: 2,720 x 4
# Groups: State [54]
State Hospital.Name `heart attack` rank
<chr> <chr> <dbl> <int>
1 AL SOUTHEAST ALABAMA MEDICAL CENTER 14.3 1
2 AL MARSHALL MEDICAL CENTER SOUTH 18.5 1
3 AL ELIZA COFFEE MEMORIAL HOSPITAL 18.1 1
4 AL ST VINCENT'S EAST 17.7 1
5 AL DEKALB REGIONAL MEDICAL CENTER 18.0 1
6 AL SHELBY BAPTIST MEDICAL CENTER 15.9 1
7 AL HELEN KELLER MEMORIAL HOSPITAL 19.6 1
8 AL DALE MEDICAL CENTER 17.3 1
9 AL BAPTIST MEDICAL CENTER SOUTH 17.8 1
10 AL JACKSON HOSPITAL & CLINIC INC 17.5 1
# ... with 2,710 more rows
任何人都可以帮我找出为什么它不起作用吗?
运行'订单(订单( '心脏发作') )',你会发现它总是返回1(因为你传递了一个长度为1的字符向量)。我假设你打算使用反引号('''')而不是单引号(''')。 – alistaire
^换句话说,R不会将'心脏病发作'识别为列名。它认为你正在试图告诉它排列单词_heart attack_。把名为'心脏病发作'的列放入并取出额外的'order()',它应该可以正常工作。 –